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# HW6 - PROBLEM 3.5 A foot valve for a pneumatic system is...

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Unformatted text preview: PROBLEM 3.5 A foot valve for a pneumatic system is hinged at 3. Knowing that a = 28°, determine the moment of the 4-119 force about point B by resolving the force into components along ABC and in a direction perpendicular to ABC. _J SOLUTION First resolve the 4-lb force into components 1’ and Q, where Q : (4.01b)sin23° = 1.8778711) Then ME = r1139 = (5.51n.)(1.87787 1b) = l2.2063 lb-in. or MB :12.211b-in.‘)4 l— g; 5/ WM MAL PROBLEM 3.12 It is known that a force with a moment of 7840 lb- in. about D is required to straighten the fence post CD. If a = 8 in., b = 35 in., and d = 112 in, determine the tension that must be developed in the cable of winch puller AB to create the required moment about point D, g4 n—J—J. SOLUTION C ,1 l 35 7 " 35 in, TAB D I: T 135’ [— AB ’4— Ha £n_——ﬂl 8 in Slope of line EC 2 35—1"; = l 112 m + 8111. 24 24 Then TABx = ET” 7 and TAB)! I ETAB Have MD : TABx(y) + TAB<v(x) 24 7 78401b-in. = ELF/13(0) + 57450121“) TAB = 250 lb or TAB = 2501b 4 SOLUTION (42) Have where Then and Have where Then and AxB: PROBLEM 3.17 A plane contains the vectors A and B. Determine the unit vector normal to the plane when A and B are equal to, respectively, (a) 4i — 2] + 3k and 72i+6j—5k, (b)7i+j—4kand—6ii3k+2k. A: AKB iAxBl A=ﬁ7ﬁ+K B=—2i+6j75k j k AxB: 4 —2 3=(10—18)i+(-6+20)j+(24—4)k:2(—4i+7j+10k) 72 6—5 \A x 31: 2 (—4)2 + (7')2 + (10)2 : 2% w or A=+Hi+n+wkl< 2J165 165 AXB 3‘: leBl A=7i+j—4k B=—6i73j+2k k l —4 =(2—12)i +(24—14)j+(721+6)k = 5(—2i +2j—3k) 2 \A x 3| : :s,/(—2)2 + (2)2 + (—3)2 = sJﬁ 5(-2i+2j—3k) 1 1=_— 1:7 546 °’ ﬁ( -2i+2j—3k)< ...
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HW6 - PROBLEM 3.5 A foot valve for a pneumatic system is...

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