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Unformatted text preview: 33.57 A iJZ—kg collar C may siideiwitiaout friction along a horizontal rod.  C _
It is attached to three springs, each of constant k 2 400 N/m and ‘  . .4431;
ISQ—mm undeformed length. Knowing that the coilar is released ‘ . . ..
from rest in the position shown, cietermine the maximum speed it a» kﬂﬁgwf 1% T
n will reach in the ensuing motion. ‘ ‘ mfﬁé I x‘ 13%. 32%
M 3% 350 mm
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M ebquifluM f \: 5
a We, CM 8% Fig. 1:13.57 ’1 D ‘5 T. +\/‘ 1' i”; i“ V:
7.70
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”>me Vcb‘. Ji¥LtOOM (,OOlijlhjL : 1772/ MM
i W\
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i “A AC X: 1";0Wm ill/36.6{f01‘mm VIN,“ likqocD’E(,H’5Liioznjl 3 ¢.(o\‘75L//UW1 BOOWM \ V‘ : \lnéc‘gr vco‘ + VAC! 1 [j 4 r771l MM .1, 6.970! mm 3 7.6?75/Vm n V2“: 291%) , 2(74975/6’; — AWLQMW)
Wu H #29? V?“ 2 “2.1722. "“751— (V: 3N1 “/51 Kim
V5” f7 13 67 The system Shown is in ( quilibrium when tﬁ = 0 Knowing III; II
iII'Itialiy d)": 90” and that biock C is Uiven a slight nudge when the system Is III that position determiné the speed. of the block as
It passes through the equiiiinum position rﬁv m 0. Neglect the weight (If the ram} "FHA :. [3+U2' BiacK reams max:mwm 513% am ‘ I
Pisa/L21" MUM?“ ¢©W"I:LNWM ﬁnalIran MQUWM FLMIJJ Wm itﬂ‘Iv arm/((3 Fig. P1167
ﬁw %%3’LUFIW,Dt051+lgu _ AI ebuthkw‘M }/ pi ”('A‘ﬂ 5E EMA”) : Emexjﬁ hzslIszPI LN? V5: ngIszﬁﬁf
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72: .Ivl—II ‘ W': Jab/. Viv 2——'———’j§%‘ (LIZIZ‘TW‘O‘II7HIM‘Q‘) Jig“: “V ”L 33 3201 “VS“: é13.95 Collar A weighs 10 1b and is attached to a spring of constant F“ ' .s‘
u S I :4
«.3 2‘ '2‘
””6135: 50 Ila/ft and of undeformed length equal to .18 in. The system is
set in motion with r = 12 in, of; m 16 Em. and L} w": 0. Neglecting
the mass at the rod ancl the effect of friction, dctcrmine the
radial anti transverse components of the velocity of the collar when 1' m 21 in. Gmglff‘v'u‘ifv‘m (A: “Siky W‘le. rI UB‘ : ﬁve”. K Fig; P1395 V92 ; 'ivat — ”i" » we : M2? «CL/5 3'?,7§j£+ + (9.25% = .155 23 i3 "Vﬁnill‘ +};.5g25 pf ‘ ‘ ‘P—+
WW%#iJMM§ 1
41—7 Vtsmk Vﬁwﬁz : 13,5. 173105;; 1 Z
W¢&—§+rtlwm§ﬁ%t
vi 1'
VFl ; M’émm wot/52 — (1.1%“19/5) 1 102.£8‘/?10r%z_ [ TF7? 133m p‘ jg: W 7'4 2/3 /2c9!0
7'HAM 13.§2¥ The initial \‘(.eh';:.3ity of the blm‘k in position A is {30 [11's. Knowingf
that {ha1: <2:1c,fﬁé'im1t 0? kinetic ﬁ‘iction histween the [ﬂock and the‘
piano is it": 2 0.30, (interrrm'ze the firm} if fakes far the block to
much 13 with Him velocity; if {a} 6 = (L {in} E} m 205', b 3
\VX ‘N Fig. 913.321 ‘ 0
wa<ﬂmgm9+w%£ﬂt=rvz .— yt/{Cé lane 72% m9 3mg) m) I >.~3245é_ﬁ_h 31232263 m0 1M) 2' M 30HA : ____._________ = 1.12%
m )6 31.1%.(3mlOD—M2063 L: 13.133 TE}: sysfemws'iumin‘is released f'nml i‘est.“[)(ziermine the time it
takes far the V(_:§<‘Jcéty UFA to reach i :n/s‘ Negiect Friction and the
mass 0f the glitl‘liﬂys. f“ zumwc l W + \73 :0
V5  "ZVCL 0 a 1
MM + 5‘1“ : MA VAL ‘ :ig. ”3,133 z 7:“ x:
Admin +ZMBVA>: Lug — mg; EIE (MM/141+ HMB V41 '2 2W8 ”WA 1: : VAL (w W0 ‘M —. mamm Zﬁwmsam) 10.363] 33.146 At an intersection C111 Bwas traveling 301111131111 (1111" A was it" 30° north of east wh: n thev 51 manned into each otim r 11pm: 11 tigationa it W15 {mind that «fter the crash the two cars go and skidded 011 at an angie of 10" north of cast. E21011 b C1 timed that he v. as going a? the speed limit of 50 km/h 11
he tried to slow (1011111 but (2911111111 11110111 the c1 1s11 110cm ofhie 1 drive} was; going 21101, faster Knowing E11: it the. masses: .1 and B were 1500 kg and 1201) kg,1espent§ve}y deter; {12) “111(1) (3 M was goixw 1331131 {#1) tin xpm (1 of the faster" ()1 1“!) cars 11‘. 1:111 510“ (:1 iar “as tmw 1mg at the speed 1111111. Fig. H3346 CarA‘. M11111. + if = Why{12 x: MAVAQD30°~11€ = MAVAlwlob 01 R U m \11 11,50 :We : mx/MMIOU (2‘)
can: 11331111: Max};
113 .o_ + 1,171 = m5 Vgicooloo (.31
:1" mgvgﬂjat: mgvhmmb (4)
K‘ VAL= U51 : UL
4.111031%; 5 11:11:11,112, :06 We (3541113 Ml‘wﬁm
MAVAICCD 30" 1 MA V2w31001‘14/[3V7‘Cﬂj100 (5)
W W, M300 ”Mavis: *— “4141/1 MMOO + W13 UzM (0° Q.) 501% @\‘1’((3) 13:71“ V2 M (611.518 “MU/1. mjoo : U1\L¢D{00<MA,+M3>
M1U4,M300VI{5\}3 1‘ U2M10°CVMA+W13)
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n \12 : MW MW°(M1*MB> {KM(L Z/Z \‘ . C)
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\jﬁ" >2 V81 MW : ﬁﬂ— V5, MA (mja‘iwao vwaaawow‘) {500,13 (wsawwhmwmm‘) VAN: V8! X 230% TRUE); )VA.>\)5(' n in) V6}: 50 [rm/hr VAN 2.30m Earn/w \v“ MW Km/w /* (‘1 5:33.51 A l—25I g ball moving 211211 speed of 3 111/5 strikes a 250 g pigle sup 4 1 .j ‘ n‘
ported by springs AssumintI that 1'10 811315;); is lost 111 the impact, 125 g® ‘ ‘
determine ((1)1111: velocity of the ball 111111113111 1teh after impact  H V
(b) the impulse of the three exerted by the p11 lte on the b1 11]. No QK+€(M‘10L?1U«)[$€5 So W+W ;3 __
00115421114. Mao 9448131 '13 Came/1nd Fig 1113.151 1 [Mac/1:615 will 1121112 611st uni1.1.51 11110;“ be, [1117ij * lq+ﬁf.
0
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/m\L\/b1 1 /2/M5Ubl *’%'MPVP21 aria/77 (I) V171 2. mLLVblquv 6J5+Iiwi~¢ {4453 1450(2) (”\x 35.156 s’l'wo Hiawatha]. hockey pucks are moving ()1: z: hmckey rink at the
same: speed of 3 mi}: and in 1711111110? and opposiie directitms when
they strike each other as shown Assuming 21. ctniafﬁcimi of restﬁ 1.1
tim‘m 2‘ .1, detcmiim: tin: magniiucie‘ and direction (£11m velocity
' of each puck afim' impact. vatm “mam—vii) <2) I// UP:
(7/(107 /3 The three biocks shown are identical. Blocks 8 and C are at
rest when block 3 is hit by block A, which is moving with a
velocity VA of 3 ftfs. Aﬁer the impact. which is; assumed to
be perfectly plastic (820), the velocity of blocks A and B
decreases due to friction, whiie block C picks up speed, until
all three biocks are moving with the same velocity v‘
Knowing that 1113 coefﬁcient of kinetic friction between all
surfaces is ,u,‘ 20.20, determine (a) (in: time required for the
three biocks to reach [he same velocity, (1)) the totai distance
traveled by each block during that time. PROBLEM 13.182 EMMgﬁkit¥C\& «5ng ”VFWi7 began: hidek55('~&i)mrnsmiwm (5
Con.5eriI€=X. Vc’ =0 lbs—maul £5 biicﬂidﬁ a 0 r a?
Mil/H'Mevjﬂ‘ﬂcz *— Mil/4 T‘MBVAIrvvwcjz} MAEszmCI} 63.0150 UAILUJ/ZV/ 9M1». = dawn75W}! . Lyn/l {VIZVA/Z [I] @_c ‘
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13.186 Ball B is hanging from an inextensible cord. An identical ball‘Ais
released from rest when‘it is just touching the cord and drags
through the'verticaldistance ILA —"' 8 in. before striking balIB.
Assuming e m 0.9 and110 friction, determine the resulting maxi
mum vertical. dispEacement hf, of the bail B.
V...
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Ca; 9 : J‘tﬁ «1 _ J}— Fig. 913.136
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 Summer '08
 Matthews
 Dynamics

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