Dynamics_HW5_solution_9th_ed

# Dynamics_HW5_solutio - p‘ jg W 7'4 2/3/2c9!0 7'HAM 13.§2¥ The initial\‘.eh.3ity of the blm‘k in positit‘m A is{30[11's Knowingf

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Unformatted text preview: p‘ jg: W 7'4 2/3 /2c9!0 7'HAM 13.§2¥ The initial \‘(.eh';:.3ity of the blm‘k in positit‘m A is {30 [11's. Knowingf that {ha-1: <2:1c,-fﬁé'im1t 0? kinetic ﬁ‘iction histween the [ﬂock and the‘ piano is M I: 0.30, (interrrm'ze the firm} if fakes far the block to much 13 with zen; velocity; if {a} 6 = (L {in} E} m 205', b 3 \VX ‘N Fig. 913.321 ‘ 0 wa<ﬂmgm9+w%£ﬂt=rvz .— 3mg» ) %%%%97ﬂ%m«9 m) I >.~3245é_ﬁ_h 31212263 m0 1M) 2 30HA : W" =- 1.12% m )6 31.1%.(3mlOD—M2063 13.125 A truck is traveiing down a road with a 4-percent grade at a speed“ of 60 mm when its brakes are apph’ed to slow it down to 20 mi “.E; An antiskid braking system limits the braking force to a valucéfé at which the wheels of the truck are just about to slide. Knowing? that the coefficient of static {fiction between the road and théﬁéj wheels is 0.60, determine the shortest time needed for the trubk to slow down. §= 2.2m? - 14 - my Woﬁ¢ t<£ﬂh€~ayga6>£1 20“ "3-29 A iight train made bf two cars travels at A15 milk. Cen‘ A weighs 45 mm; 18 fans; and car 8 weighs IE3 tons. When the brake-35 are applied, W , . ‘ A 18 tons 3 15 mm aycqns‘tnnt ‘brglking fbrce \$430011)! is applieci in each car. Deter— mine (a) the time required for the train £0 stop after the brakes p are applied, (I?) the force‘irl thalamplmg behvccn ﬁlm cars whiie the {min is shawing down” ' ' ‘ x? N Fig. 933.129 ‘0 a M V91 1’ Ni 4— H : / a) k f E W: E J“ Why/{2 {M1 :‘x/Al : V31 : Ul If 1 IHECWHQW—wa saws 32,2.A 350OK'2x’4300 .IC 1 1! .7776. Li 1L\.77é§’ F M yujooﬂa +»A)->&+ . 70 MBVB 4‘21: 8V7... £1 ‘— * W'BVG. z": 7, M : ‘- ‘Muﬁ L-F+q3r00§f 1 ‘WIBV5l f; “ MUg ﬁLIFFO) _ “mm; : ~— mew. u—____.—-"' 1: F 2 HBOO/M mﬂ': 435:0 m1— ggffgfﬁkawh slaw/M I 1:6? M (V? 360% 'ILI.77'7_S a; ; Hgoon; —360¢.,‘H LL: N _ CoJcL Laue, 000W? grim-(01\$ f— “ G (“WHICH m1 (,va +0 TE}: sysfemws'iumin‘is released f'nml i‘est.“[)(ziermine the time it takes far the V(.:§<‘Jc-éty UFA to reach i :n/s‘ Negiect Friction and the mass 0f the glitl‘liﬂys. f“ zumwc ‘ fig. 1913,13: 1‘: “- L V I- l mi_£_La—WAB T? "Merk/Jﬁ t _ MW; 2V 42: mﬂﬂi MAM] ixwﬁ + LUJS‘ 4* -‘MA\]A1 2MB VA -.: - WA jg (MM/141+ HMB V41 '2 2W8 "WA 1: .. in‘é’lfi (Ska-1&9) .0 .- VAL (MA + 4M5) ZQLW‘AW'Q 10.363] 33.146 At an intersection Car Bwas traveling somh‘and car A was 30° north of east when they slammed into each other, Upon"i: tigationitwas {mind thzit’after the-crash-~the two carslgo and skidded GET ‘at: an angie of £0“ north of cast. Each b claimed that he was going-gaf- the speed limit of 50 km/h :1 he fried to slow doxim but ccmldn't avoid the crash beam ofhm“ driver was; going 2110f, faster. Knowing that the. masses'- ’ A and B were 1500 kg and 1200 kg, respectiveiy, (£6196; {a} whic?) car was goiug faster, {3}) the. Speed of the fasteme two cars if the slower car was traveling at the speed limit. Fig. H3346 CarA‘. mp; ml + if = Why-{12 x: MAVA|C¢D30°~TLK9€ = MAVAlwlob (W. MAVA‘Mwoglﬂk : MAVMMIOU G7 Cuff) mﬂwii: maf/‘BL 2:3 -.o_ + Ixi = m5 Vgicooloo (.3) a: -mgvgﬂjat: mﬁvhmmb (q) p VAL= U51 : V; m 03 Ha ﬁd-‘wwﬁa :06 me (354% ml-‘wﬁm mﬁvAlCCD 30" : MﬁvgmmDerngcmma (5) MA UMMBDoumﬂvﬂl : MAV1MIOD+M£UZMIO° L6) ﬁohrﬁ 130:“ V2 M 26:1.»th MAVA‘ (103300 : U1 ‘55) [00<W1A,+ng> MAU4,M300-M\$\ng 1‘ U2M10°CVMA+M3) V2: W Q910°ﬁMK++MIQ n \jz : MW MW°(MI+*MB> {KM-(L Z/Z MAUA.C.§3300 ‘ MﬁVAIMBOa M3VE @Iaywﬂ m/a"(m m p o v " . WAUAlCdjaC) M10” = mvﬁ,m300m/&D—- wrva 93:00 ‘ \\ .- - - 0 VA,(mmaoDM/00~m4m30°w/&?> - *‘MaVsrmw 0 __ 0 w"; Val M z m W m, MA (mja‘iwao vwaaamw‘) {500,13 (Casawwhma/wﬂ) VAN: Val X TRUE); )VA.>\)5(' n in) V6}: 50 [rm/hr VM: 2.30% Earn/w “W Km/w /* ('W ball moving at £1 speedfo'f 3 a 250—gpiate 511p- :ported by Springs. Aésmn'ing that fie energy is'hs‘t- in the impact, kietermineam) the velocity" of the'ball iiﬁﬁkdiafék after impact, (19) the impulse of the three exerted by the plate on the bell. 1+. Fig. 3313.151 No efoermJ ‘metdsesJ So W+m £3- WSQU-Vbﬂ. f’dso ed/lelfabt 13 CWLEQV‘KW—tx I D;,¢c,k;m WJI MP '02 @st enema w Wm be, range [q’rer. l W‘i‘m 0) m anti/77 6J5+I+J~¢ {44-53 MILO 2) ML vbll "Z, Vn ML V1921 1+ WLP (Vb: -Vbz\] w 2 M52} + 235\$ W Mr 3 1/ (be'lVblVLl + ng ...
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## This note was uploaded on 05/17/2011 for the course EGM 3400 taught by Professor Matthews during the Summer '08 term at University of Florida.

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Dynamics_HW5_solutio - p‘ jg W 7'4 2/3/2c9!0 7'HAM 13.§2¥ The initial\‘.eh.3ity of the blm‘k in positit‘m A is{30[11's Knowingf

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