Rigid tank and piston prob

Rigid tank and piston prob - Closed System Analysis Using...

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Closed System Analysis Using Property Data The “rigid tank” Example (What is constant with this type example?) Tank contains water Pressure is measured as 15 psig Temperature is measured as 75 deg F Tank and contents weigh 40 lbm. Tare weight of tank is 15 lbm so water weighs 25 lbm. What is the state of the water in the tank and confirm that the tank size is approximately 0.4 ft 3
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Closed System Analysis Using Property Data The “rigid tank” Example Tank contains water Pressure is measured as 15 psig Temperature is measured as 300 deg F Tank and contents weigh 40 lbm. Tare weight of tank is 15 lbm so water weighs 25 lbm. We don’t know the volume of the tank in this example. What is the state of the water? And what would tank volume have to be?
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The “rigid tank” Example Tank contains water Pressure is measured as 15 psig Volume of tank is 370 ft3 Site glass indicates that 25% of the tank volume is liquid. Assume equilibrium conditions.
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This note was uploaded on 05/18/2011 for the course EML 3100 taught by Professor Sherif during the Spring '08 term at University of Florida.

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Rigid tank and piston prob - Closed System Analysis Using...

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