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Act.02.02

# Act.02.02 - but what surface should we choose(Hint remember...

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Physics 2102 Section 002 September 8, 2010 Activity 1 The figure shows four solid spheres, each with charge Q uniformly distributed through its volume. Rank the spheres according to the magnitude of the electric field they produce at the point P: (i) all tie (ii) (a) = (b) > (c) = (d) (iii) (a) = (b) > (c) > (d) (iv) (a) > (b) > (c) > (d) (v) (d) > (c) > (b) > (a) Activity 2 The figure shows a cross section of a spherical metal shell of inner radius R. A point charge of –5.0 μ C is located at a distance R/2 from the center of the shell. The shell is electrically neutral. Our goal is to find the magnitudes and signs of the (induced) charges on the inner and outer surfaces of the metal shell. (a) First, let’s find the (induced) charge on the inner surface of the metal shell. We will use Gauss’ law –

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Unformatted text preview: but what surface should we choose? (Hint: remember that the electric field inside a conductor is zero). Once you have chosen this surface, it is easy to see what the induced charge on the inner surface must be (use Gauss’ law with the surface from (a)). (b) Now you can calculate the charge on the outer surface (Hint: Remember, the metal shell is electrically neutral). (c) Next consider a similar problem. A conducting spherical shell has an excess charge of +10 C. A point charge of -15 C is placed at the center of the shell. Use Gauss’ law to calculate the charge on the inner and outer surfaces of the shell, choose one of the answers below: (i) Inner surface +15 C, Outer surface +10 C (ii) Inner surface 0, Outer surface +10 C (iii) Inner surface +15 C, Outer surface -5 C...
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