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Unformatted text preview: density through this cross section varies with radius r as J = ar 2 . We want to calculate the current through the outer part of the wire, between radius R/2 and R . To do this we must set up an integral over J • dA (i) What are the directions of the current density J and the area vector dA in this case? (ii) Part (b) shows a differential area dA of the wire, in the shape of a thin ring. Express dA in terms of radius r . (iii) Set up the integral over the current density and calculate the current through the outer part of the wire:...
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This note was uploaded on 05/20/2011 for the course PHYS 2102 taught by Professor Gimmnaco during the Fall '08 term at LSU.
 Fall '08
 GIMMNACO
 Physics, Charge, Current

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