Act.02.25

# Act.02.25 - i 1 smaller than the same as or bigger than i...

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Physics 2102, February 25, 2011. Activity 1: A potential difference of 3.00 mV is set up across a 2.00 cm length of copper wire with a radius of 2.00 mm. (a) Calculate how much charge drifts through a cross section of the wire in 3.00 ms: (b) Calculate the magnitude of the electric field in the wire Physics 2102, February 25, 2011. Activity 1: A potential difference of 3.00 mV is set up across a 2.00 cm length of copper wire with a radius of 2.00 mm. (a) Calculate how much charge drifts through a cross section of the wire in 3.00 ms: (b) Calculate the magnitude of the electric field in the wire

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Activity 2: The figure shows a copper wire, connected to a battery with potential difference V = 12 V. Half of the wire has a radius of r= 1.0 mm and length L = 1.0 m, the other half has a radius r/2 and length L = 0.5 m. The resistivity of copper is ρ = 1.7 x 10 -8 Ω m. (a) Is the current
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Unformatted text preview: i 1 smaller than , the same as , or bigger than i 2 . (b) Is the resistance R 1 smaller than , the same as , or bigger than R 2 . (c) Is the potential difference V 1 smaller than , the same as , or bigger than V 2 . (d) Calculate the total energy dissipated in the whole wire in 10 minutes: Activity 2: The figure shows a copper wire, connected to a battery with potential difference V = 12 V. Half of the wire has a radius of r= 1.0 mm and length L = 1.0 m, the other half has a radius r/2 and length L = 0.5 m. The resistivity of copper is = 1.7 x 10-8 Ω m. (a) Is the current i 1 smaller than , the same as , or bigger than i 2 . (b) Is the resistance R 1 smaller than , the same as , or bigger than R 2 . (c) Is the potential difference V 1 smaller than , the same as , or bigger than V 2 . (d) Calculate the total energy dissipated in the whole wire in 10 minutes:...
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## This note was uploaded on 05/20/2011 for the course PHYS 2102 taught by Professor Gimmnaco during the Fall '08 term at LSU.

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Act.02.25 - i 1 smaller than the same as or bigger than i...

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