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formulas_CH302

# formulas_CH302 - ln K 2 K 1 = ∆ H r xn R 1 T 1-1 T 2 K w...

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FINAL EXAM FORMULAS CH 302 R = 8.314 R = 0.08206 L atm mol K 0°C = 273.15 K 1 atm = 760 torr 1 F = 96485 C density of water = 1.00 g/mL SH ice = 2.09 J/g C SH ˚ water = 4.184 J/g C ˚ SH steam = 2.03 J/g· C ˚ H fus = 334 J/g H vap = 2260 J/g (all these values for water) PV = n RT P total = P A + P B + P C = MRT π P solvent = X solvent · P 0 solvent T f = ik f · m T b = ik b · m x = - b ± b 2 - 4 ac 2 a P solvent = X solute · P 0 solvent heat = SH · m · T heat = H · m ln[A] 0 - ln[A] t = akt [A] 0 - [A] t = akt - = akt t 1/2 = [A] 0 /2ak t 1/2 = 1/ak[A] 0 t 1/2 = ln(2)/ak k = A· e ln P 2 P 1 = H vap R 1 T 1 - 1 T 2 ln k 2 k 1 = E a R 1 T 1 - 1 T 2
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Unformatted text preview: ln K 2 K 1 = ∆ H r xn R 1 T 1-1 T 2 K w = [H + ][OH-] pH = -log[H + ] pOH = -log[OH-] pH + pOH = 14 pH = pK a + log [A-] [HA] K p = K c (RT) ∆ n pOH = pK b + log [BH + ] [B] G = Gº + RTln(Q) ∆ ∆ Gº = -RTln(K) ∆ E = E-RT nF ln Q G = -∆ n FE E = E-0.0592 n log Q One Ampere = one Coulomb/second Faraday = 9.649 x 10 4 C/mol.e-...
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