Assignment 3 - 2 1 2 2 2 = = gt b s m 5 24 s 5 2 s m 80 9 2...

This preview shows pages 1–2. Sign up to view the full content.

Assignment: Refer to your book “University Physics by Young, Freedman and Ford 12 th Edition”. Copy and answer with complete solution the following Exercises. Answers and graphs were provided. Your assignment must be handwritten. 2.1: a) . s m 197 b) s m 169 2.3: min. 70 2.8: a) s m 80 . 2 b) s m 2 . 5 c) s m 6 . 7 2.9: a) At 0 , 0 1 1 = = x t , so . s m 0 . 12 av = = v b) , ) s m 360 . 0 ( ) s m 80 . 4 ( 2 3 2 t t v x - = so i) , 0 ) 0 ( = x v ii) , s m 0 . 15 s) 0 . 5 )( s m 360 . 0 ( ) s 0 . 5 )( s m 80 . 4 ( ) s 0 . 5 ( 2 3 2 = - = x v and iii) . s m 0 . 12 s) 0 . 10 )( s m 360 . 0 ( ) s 0 . 10 )( s m 80 . 4 ( ) s 0 . 10 ( 2 3 2 = - = x v c) The car is at rest when 0 = x v . Therefore 0 ) s m 360 . 0 ( ) s m 80 . 4 ( 2 3 2 = - t t . The only time after 0 = t when the car is at rest is s 3 . 13 = t 2.21: a) . s m 00 . 5 0 = x v b) , s m 43 . 1 2 = x a 2.24: . s m 0 . 70 = x v 2.29: a) Interpolating from the graph: left) the (to s cm 3 . 1 , s 0 . 7 At right) the (to s cm 7 2 s, 0 . 4 At - = + = v . v b) 2 s cm 3 . 1 - = a which is constant c) = x area under v - t graph First 4.5 s: Triangle Rectangle A A x + = ( 29 ( 29 cm 5 . 22 s cm 6 s 5 . 4 2 1 s cm 2 s 5 . 4 = + = From 0 to 7.5 s: The distance is the sum of the magnitudes of the areas. ( 29 ( 29 cm 5 . 25 s cm 2 s 5 . 1 2 1 s cm 8 s 6 2 1 = + = d d)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
2.42: a) m. 6 . 30 s) 5 . 2 )( s m 80 .
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ) 2 1 ( 2 2 2 = = gt b) s m . 5 . 24 s) 5 . 2 )( s m 80 . 9 ( 2 = = gt . c) 3.60: a) x = 6.93 m. b) c) m 3 6 . x = , so the man will not be hit. 3.63: a) y = m 15 .-, the change in height. v = 17.8 m/s. b) 28.4 m from the near bank 3.67: Take y + to be downward. a) ? m, 20 , m/s 80 . 9 , 2 = =-= = t y y a v y y s 02 . 2 gives 2 2 1 = + =-t t a t v y y y y The rock must travel 100 m horizontally during this time, so m/s. 49 = x v b) ? m, 45 , m/s 80 . 9 , 2 = =-= = t y y a v y y s 03 . 3 gives 2 2 1 = + =-t t a t v y y y y During this time the rock travels horizontally m 150 = s The rock lands 50 m past the foot of the dam....
View Full Document

{[ snackBarMessage ]}

What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern