Assignment 3 - 2 1 2 2 2 = = gt b s m 5 24 s 5 2 s m 80 9 2...

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Assignment: Refer to your book “University Physics by Young, Freedman and Ford 12 th Edition”. Copy and answer with complete solution the following Exercises. Answers and graphs were provided. Your assignment must be handwritten. 2.1: a) . s m 197 b) s m 169 2.3: min. 70 2.8: a) s m 80 . 2 b) s m 2 . 5 c) s m 6 . 7 2.9: a) At 0 , 0 1 1 = = x t , so . s m 0 . 12 av = = v b) , ) s m 360 . 0 ( ) s m 80 . 4 ( 2 3 2 t t v x - = so i) , 0 ) 0 ( = x v ii) , s m 0 . 15 s) 0 . 5 )( s m 360 . 0 ( ) s 0 . 5 )( s m 80 . 4 ( ) s 0 . 5 ( 2 3 2 = - = x v and iii) . s m 0 . 12 s) 0 . 10 )( s m 360 . 0 ( ) s 0 . 10 )( s m 80 . 4 ( ) s 0 . 10 ( 2 3 2 = - = x v c) The car is at rest when 0 = x v . Therefore 0 ) s m 360 . 0 ( ) s m 80 . 4 ( 2 3 2 = - t t . The only time after 0 = t when the car is at rest is s 3 . 13 = t 2.21: a) . s m 00 . 5 0 = x v b) , s m 43 . 1 2 = x a 2.24: . s m 0 . 70 = x v 2.29: a) Interpolating from the graph: left) the (to s cm 3 . 1 , s 0 . 7 At right) the (to s cm 7 2 s, 0 . 4 At - = + = v . v b) 2 s cm 3 . 1 - = a which is constant c) = x area under v - t graph First 4.5 s: Triangle Rectangle A A x + = ( 29 ( 29 cm 5 . 22 s cm 6 s 5 . 4 2 1 s cm 2 s 5 . 4 = + = From 0 to 7.5 s: The distance is the sum of the magnitudes of the areas. ( 29 ( 29 cm 5 . 25 s cm 2 s 5 . 1 2 1 s cm 8 s 6 2 1 = + = d d)
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2.42: a) m. 6 . 30 s) 5 . 2 )( s m 80 .
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Unformatted text preview: ) 2 1 ( 2 2 2 = = gt b) s m . 5 . 24 s) 5 . 2 )( s m 80 . 9 ( 2 = = gt . c) 3.60: a) x = 6.93 m. b) c) m 3 6 . x = , so the man will not be hit. 3.63: a) y = m 15 .-, the change in height. v = 17.8 m/s. b) 28.4 m from the near bank 3.67: Take y + to be downward. a) ? m, 20 , m/s 80 . 9 , 2 = =-= = t y y a v y y s 02 . 2 gives 2 2 1 = + =-t t a t v y y y y The rock must travel 100 m horizontally during this time, so m/s. 49 = x v b) ? m, 45 , m/s 80 . 9 , 2 = =-= = t y y a v y y s 03 . 3 gives 2 2 1 = + =-t t a t v y y y y During this time the rock travels horizontally m 150 = s The rock lands 50 m past the foot of the dam....
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