This preview shows pages 1–4. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview:  sand)P(sand) + P(2  clay)P(clay)+ P(2  rock)P(rock)] – P(2  clay)P(clay) = (100/250) + [(10/100)(100/250) + (2/100)(100/250) + (2/50)(50/250)] – (2/100)(100/250) = 112/250 = 0.448 (e) Dependent , because, for example, P(rock AND 0) = 0.176 [see (c)] ≠ P(rock)P(0) = (50/250)(212/250) = 0.170 7. (a) P(steep AND 3) = 2/80 = 1/40 (b) P(mild OR 2) = P(mild) + P(2) – P(mild and 2) = 30/80 + 10/80 – 4/80 = 36/80 = 9/20 (c) P(mild  1) = P(mild and 1)/P(1) = (10/80)/(21/80) = 10/21 (d) If independent, P (flat and 2) = P(flat) x P(2) = (40/80) x (10/80) = 400/6400 = 1/16 Therefore, the number of hills with flat and 2 is 80 x 1/16 = 5 8. 9. Variability in horsepower is clearly greater in the US and least in Sweden and Italy....
View
Full
Document
This note was uploaded on 05/19/2011 for the course CEE 110 taught by Professor Stolzenbach during the Spring '08 term at UCLA.
 Spring '08
 Stolzenbach

Click to edit the document details