Solutions PS 1 F08

Solutions PS 1 F08 - L Problem #4: I mole algae(mol urt...

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CEE 153 SOLUTION SET ryBKtl Problen #1: a) e = lmg looomt =Fgrg.l 100mI L ll,l b) Multiply 100 ml by the water density: roo*'S.#=o.lfts:Hzo O.ltg H'Ox'lfu' = l05mg HzO 'kg lns As lars As l0'mg HrO + lrng As lO'mg Total lOnnc As c==-31.=WiA lO'mg Total c) Gram molecular weight of Araenic (As) is 74929 .'" #nroles As = lmg x t a ic * t€ ;gote = 1.3 x l0-5 g - mole mg 74.929 l.3xl0-5s-mole l0ffimt C=-----e.X- l00nd L =1.3x10{ 9-Yole L Problem #2: f ( n =273 +25 =298 K fi=32.06+(2x16)=64.06 dwm\=,(*%,).#.##-m ) = 0.153ppttt c( onml= 400 F€ * l0-3 mg * 22'4 * 298'K * lsrm - m' pg 64.06 273"1K lat*t Page

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Problem, #3: Molecular weiphts N= 14 O* 16 H:l NH3 = 17 NOr:46 NOr- = 62 Compute amount of each comoor,rnd that is nitrggen fN) Ammonia = 39 T8 * 14 =24.71ffi9 EI7 L Nitrite = 0.10 t8 x 14 = 0.03 *8 L 46 L Ni&te = I.5 *8 r 14 = 0.34 ffi8 L62 L Orsanic N = 15 m.{ *11= ls.oIE' LT4 L Total {N} = (?4.?l + 0.03
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Unformatted text preview: L Problem #4: I mole algae(mol urt :^l_9-7glp-mole) consumes 8 mores of o2(mol wt:32 g/g-mole) or 197 galgae consumes256 gA2 lg.5 *s.ot Total BoD L ...lsalgee" 2569 or -L l9?galgae ProFlBmf5; I acre-foot = 1233.49 m3 .'.600,000 acre-ft = 7.4xlUEm3 ='l.Axl}rrkg =7.4 e * g00ppac = g00x10{ to'{s rt fons HrO xl}stons HrO (metric) ::fT* = (800 x I 0{y?.4 x I 08 ; = i92" 000 tons salt 6"t i" Page2 of 3 Problem lf6: a)c"=t=ffi=ro-2\$=m Therefore. just meets the standard. b)c*=c"*frs- =rory=F?l Therefore. does not meet the standard. ProFlem #7: a) rh"=CnQn+CrQu ^"=(row.o'+).['T"*g)-'.0#"#.#=F.'oe & = 0.136 b) h"=C"Que dQ"=Qn+Q, . r"4gsC .'.C--aL= =r s -=lq.elryl " Q" o.rli+o.zli I L I \$.s c) c^=cn+(c, -c,) *=c, +(c" -c)J-c',=o *(+.otg-rlf. ,ti% ,,.l-n " '\ "-' r " )lo'rl/+MnA ) Page 3 of3...
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This note was uploaded on 05/19/2011 for the course CEE 153 taught by Professor Stolzenbach during the Fall '08 term at UCLA.

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Solutions PS 1 F08 - L Problem #4: I mole algae(mol urt...

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