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sm_ch18

Water Resources Engineering

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Solutions to Chapter 18 Water Resources Engineering 18.1.1, 18.3.1, 18.4.1, 18.5.1, 18.6.1, 18.6.2, 18.8.1, 18.8.2, 18.9.1 18.1.1 Given sand, D 50 = 0.205 mm, ρ s = 2,650 kg/m 3 , and ν = 1.308 x 10 -6 m 2 /s, compute fall velocity and plot velocity with time. As shown in the spreadsheet below, the terminal velocity was found to be 0.0289 mps . The sketch shows that the terminal velocity is achieved very quickly.

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18.3.1 A fine sand particle, mean size = 0.25 mm, forms a wide rectangular channel bed with depth = 5.0 m and S 0 = 0.0003, ν = 1.308 x 10 -6 m 2 /s, and S.G. = 2.7. Compute the critical shear stress and actual shear stress, and explain what will happen under this flow condition. As shown in the spreadsheet below, the critical shear stress was found to be 0.22 N/m 2 , whereas the actual shear stress was found to be 15.7 N/m 2 . Since the actual stress exceeds critical stress, transport is expected .
18.4.1 Using the Meyer-Peter and Muller formula, compute the sediment discharge per

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sm_ch18 - Solutions to Chapter 18 Water Resources...

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