sm_ch18

Water Resources Engineering

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Solutions to Chapter 18 Water Resources Engineering 18.1.1, 18.3.1, 18.4.1, 18.5.1, 18.6.1, 18.6.2, 18.8.1, 18.8.2, 18.9.1 18.1.1 Given sand, D 50 = 0.205 mm, ρ s = 2,650 kg/m 3 , and ν = 1.308 x 10 -6 m 2 /s, compute fall velocity and plot velocity with time. As shown in the spreadsheet below, the terminal velocity was found to be 0.0289 mps . The sketch shows that the terminal velocity is achieved very quickly.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
18.3.1 A fine sand particle, mean size = 0.25 mm, forms a wide rectangular channel bed with depth = 5.0 m and S 0 = 0.0003, ν = 1.308 x 10 -6 m 2 /s, and S.G. = 2.7. Compute the critical shear stress and actual shear stress, and explain what will happen under this flow condition. As shown in the spreadsheet below, the critical shear stress was found to be 0.22 N/m 2 , whereas the actual shear stress was found to be 15.7 N/m 2 . Since the actual stress exceeds critical stress, transport is expected .
Background image of page 2
18.4.1 Using the Meyer-Peter and Muller formula, compute the sediment discharge per
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

This document was uploaded on 05/19/2011.

Page1 / 9

sm_ch18 - Solutions to Chapter 18 Water Resources...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online