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Unformatted text preview: independence); – P(A∩B ∩C) = P(A)P(B)P(C) 4 STAT 225, Dallas Bateman, Spring 2010 Independence Example • Suppose that a man and a woman each have a pack of 52 playing cards. Each draws a card from his/her pack. Find the probability that they each draw the ace of clubs. 5 STAT 225, Dallas Bateman, Spring 2010 Independence Example • We define the events: – A = probability that man draws ace of clubs = 1/52 – B = probability that woman draws ace of clubs = 1/52 • Clearly events A and B are independent so: P(A∩B) = P(A)P(B) = 1/52 * 1/52 = 0.00037 That is, there is a very small chance that the man and the woman will both draw the ace of clubs. 6 STAT 225, Dallas Bateman, Spring 2010...
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 Spring '08
 MARTIN
 Probability theory, Playing card, Dallas Bateman

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