{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Lecture13[1] - independence – P(A∩B ∩C = P(A)P(B)P(C...

Info icon This preview shows pages 1–6. Sign up to view the full content.

View Full Document Right Arrow Icon
Independence Section 4.4 1 STAT 225, Dallas Bateman, Spring 2010 Lecture 13
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Independence Two events are independent if the occurrence of one of the events gives us NO information about whether or not the other event will occur; that is, the events have no influence on each other. 2 STAT 225, Dallas Bateman, Spring 2010
Image of page 2
Independence In probability theory we say that two events, A and B, are independent if the probability that they both occur is equal to the product of the probabilities of the two individual events: P(A∩B) = P(A)P(B) 3 STAT 225, Dallas Bateman, Spring 2010
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Independence The idea of independence can be extended to more than two events. For example, A, B and C are independent if: A and B are independent; A and C are independent and B and C are independent (pairwise
Image of page 4
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 6
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: independence); – P(A∩B ∩C) = P(A)P(B)P(C) 4 STAT 225, Dallas Bateman, Spring 2010 Independence Example • Suppose that a man and a woman each have a pack of 52 playing cards. Each draws a card from his/her pack. Find the probability that they each draw the ace of clubs. 5 STAT 225, Dallas Bateman, Spring 2010 Independence Example • We define the events: – A = probability that man draws ace of clubs = 1/52 – B = probability that woman draws ace of clubs = 1/52 • Clearly events A and B are independent so: P(A∩B) = P(A)P(B) = 1/52 * 1/52 = 0.00037 That is, there is a very small chance that the man and the woman will both draw the ace of clubs. 6 STAT 225, Dallas Bateman, Spring 2010...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern