2008Midterm_2_solution - Spring 2008 Network Theory BME 311...

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Spring 2008 Network Theory BME 311 MIDTERM#2 SOLUTIONS Problem 1: (1) Since it is an ideal op-amp, V a = V b . (2) 1 2 1 4 3 4 1 2 2 0 4 3 4 4 3 2 1 2 1 1 2 0 2 0 1 1 1 0 1 R R V R R R R R V V V V R R R V R V R V V R R V R R V V R V V R V V b a b b b a a a + + = = + = = + = = (3) The expression for V 0 remains the same as (2) (4) 4 3 2 1 R R R R = (5) Since ) ( 1 2 1 2 0 V V R R V = , R 2 =R 1 is a sufficient condition.
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Spring 2008 Network Theory Problem 2: Figure 2 a b
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Spring 2008 Network Theory Problem 3: Equation (i) ) ( 10 * 6 2 ) ( 10 60 60 0 1 7 0 1 0 2 0 1 2 1 1 v v dt d v v v v v v v dt d pF k v v k v v s s + = = + Ω = Ω Equation (ii) dt dv v v V v v dt d pF k v v 0 6 0 1 0 2 2 2 1 10 * 2 . 1 ) 0 ( 20 60 + = = = Ω Combining (i) and (ii) gives us: + + = + + = 2 0 2 13 0 6 0 2 0 2 6 7 0 0 6 0 10 * 2 . 7 10 * 4 . 2 10 * 2 . 1 10 * 6 10 * 2 . 1 2 dt v d dt dv v v dt v d
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2008Midterm_2_solution - Spring 2008 Network Theory BME 311...

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