hw9_solution - t>1 1 Code: tau1=200/100 for k=...

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Mat The If th whe For At t= to c indu tlab problem current resp e initial curr ere ߬ൌܮ/ܴ the sequent =0, the switc at t=1s and uctor in term : RL circuit. ponse of a so ent is zero, t in both case ial circuit sho ch moved fro remained in s of time. (a) ource free RL the current o ݅ሺݐ es. own below, om a to b, re definitely. U L circuit (a) w ݅ሺݐሻൌܫ ݁ of a RL circui ሻ ൌ ܸ ܴ ൬1െ the initial cu maining for se matlab to with initial cu ିሺ t with voltag ݁ ିሺ urrent flowin one second. o plot the cu urrent I m is ge source V s g through th Then the sw rrent flowing (b is he inductor is witch moved g through th b) s zero. from b e
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Solution: 0<t<1, ݅ሺݐሻൌ0 .4ቆ1െ݁ ିቀ ߬
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Unformatted text preview: t&gt;1 1 Code: tau1=200/100 for k= 1:20 t(k)=k/20; i(k)=0.4*(1 exp( t(k)/tau1)); end imax=i(20); tau2=200/200; for k=21:120 t(k)=k/20; i(k)=imax*exp( t(k 20)/tau2); end plot(t,i) axis([0 6 0 0.18]) xlabel('Time,s') ylabel('Current, A') 1 2 3 4 5 6 0.02 0.04 0.06 0.08 0.1 0.12 0.14 0.16 0.18 Time,s Current, A According to the figure shown below, use circuit analysis to tell the equation for computing Vo in terms of V1, V2 and V3. Then assume V1=1V, V2=1.2V, V3=2V, use Pspice simulation to get the circuit output voltage Vo. Keys: Vo=5(V2 V1)+V3 Simulation: Vo=3V...
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hw9_solution - t&amp;amp;gt;1 1 Code: tau1=200/100 for k=...

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