hmk1 solutions-1

hmk1 solutions-1 - EEE 352Fall 2009 Homework 1 1.1...

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EEE 352—Fall 2009 Homework 1 1.1 Determine the number of atoms per unit cell in a (a) face-centered cubic, (b) body-centered cubic, and (c) diamond lattice. (a) The body centered cubic has 8 corner atoms, each of which is shared among 8 unit cells, so this gives 1 atom. Then, there are 6 face atoms, each of which is shared among 2 cells, so this gives 3 atoms. Hence, the FCC has 1+3 = 4 atoms per unit cell. (b) The body-centered cubic has 8 corner atoms, each of which is shared among 8 unit cells, so this gives 1 atom. Then, there is 1 atom at the center of the cube. Hence, the BCC has 1+1 = 2 atoms per unit cell. (c) The diamond lattice has the FCC cell with 2 atoms per position. This gives the additional 4 internal atoms. Hence, the diamond lattice has 2(1+3) = 1+3+4 = 8 atoms per unit cell. 1.2 (a) The lattice constant of GaAs is 5.65 Å. Determine the number of Ga atoms and As atoms per cm 3 . (b) Determine the volume density of germanium atoms in a germanium semiconductor. The lattice constant of germanium is 5.65 Å.
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hmk1 solutions-1 - EEE 352Fall 2009 Homework 1 1.1...

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