DCCAsummer2010 - 3 Analyze the following circuit: + 10 V 16...

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DCCA 1 DC CIRCUIT ANALYSIS - KIRCHOFF’S LAWS RESISTANCE IN SERIES - 10 V + _ R 3 = 5 R 2 = 5 1 = 10 R V V V 2 3 1 i V 1 = i R 1 V 2 = i R 2 V t = V 1 + V 2 + V 3 = i R 1 + i R 2 + i R 3 = i (R 1 + R 2 + R 3 ) = i R t V 3 = i R 3 R t = R 1 + R 2 + R 3 = 20 i t = V t / R t = 10 / 20 = 0.5 A KIRCHHOFF'S VOLTAGE LAW (KVL) The algebraic sum of the voltage drops around any closed loop is zero. KIRCHHOFF'S CURRENT LAW (KCL) The algebraic sum of the current entering and leaving any junction is zero. i i i 3 1 2 i 1 + i 2 + i 3 = 0
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DCCA 2 RESISTANCES IN PARALLEL - 10 V + _ I t R = 20 R = 20 R = 10 i i i 1 2 3 i 1 R 1 = i 2 R 2 = i 3 R 3 = V = i t R t i t = i 1 + i 2 + i 3 = V / R t = V / R 1 + V / R 2 + V / R 3 = V (1 / R 1 + 1 / R 2 + 1 / R 3 ) 1/R = 1/R 1 + 1/R 2 + 1/R 3 R t = 1/(1/R 1 + 1/R 2 + 1/R 3 ) = 5 or I t = V / R = 10 / 5 = 2 A Series/Parallel Circuits + V1 10V R5 1k R1 1k R4 0.5k R3 0.5k R2 1k
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DCCA
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Unformatted text preview: 3 Analyze the following circuit: + 10 V 16 15 45 40 V V V 1 2 3 V 4 i T i 3 i 2 Solution: STEP 1. Reduce circuit to one resistance, R TOTAL + 10 V 16 40 60 i T V 1 i 3 i 2 + 10 V 16 24 i T 40 II 60 = 1 / [(1/40) + (1/60)] = 24 R t = 24 + 16 = 40 DCCA 4 STEP 2. FIND THE TOTAL CURRENT, I TOTAL I T = 10 / 40 = 0.25 A STEP 3, 4, ETC. USE OHMS LAW TO FIND VOLTAGE DROPS V 1 = (0.25 A)(16 ) = 4V V 2 = 10 V - 4 V = 6 V I 2 = 6 V / 40 = 0.15 A I 3 = I T- I 2 = 0.25 - 0.15 = 0.10 A V 3 = (0.10 A) (45 ) = 4.5 V V 4 = (0.10 A) (15 ) = 1.5 V Voltage Division Current Division...
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DCCAsummer2010 - 3 Analyze the following circuit: + 10 V 16...

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