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Unformatted text preview: 3 Analyze the following circuit: + 10 V 16 15 45 40 V V V 1 2 3 V 4 Ω Ω Ω Ω i T i 3 i 2 Solution: STEP 1. Reduce circuit to one resistance, R TOTAL + 10 V 16 40 60 i T V 1 i 3 i 2 Ω Ω Ω + 10 V 16 24 i T Ω Ω 40 II 60 = 1 / [(1/40) + (1/60)] = 24 Ω R t = 24 + 16 = 40 Ω DCCA 4 STEP 2. FIND THE TOTAL CURRENT, I TOTAL I T = 10 / 40 = 0.25 A STEP 3, 4, ETC. USE OHMS LAW TO FIND VOLTAGE DROPS V 1 = (0.25 A)(16 Ω ) = 4V V 2 = 10 V  4 V = 6 V I 2 = 6 V / 40 Ω = 0.15 A I 3 = I T I 2 = 0.25  0.15 = 0.10 A V 3 = (0.10 A) (45 Ω ) = 4.5 V V 4 = (0.10 A) (15 Ω ) = 1.5 V Voltage Division Current Division...
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This note was uploaded on 05/21/2011 for the course CGN 3710 taught by Professor Bloomquist during the Summer '10 term at University of Florida.
 Summer '10
 BLOOMQUIST

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