# ReviewAnswers - Phys 2101 Review problems In the figure...

This preview shows pages 1–6. Sign up to view the full content.

Phys 2101 Review problems

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
In the figure below, block 1 of mass m 1 slides from rest along a frictionless ramp from height h = 3.00 m and then collides with stationary block 2, which has mass m 2 = 2m 1 . After the collision, block 2 slides into a region where the coefficient of kinetic friction k is μ k =0.6 and comes to a stop in distance d within that region. (a) What is the distance d if the collision is elastic? Ans:(4/9)h/ μ k =2.22m (b) What is it if the collision is completely inelastic? Ans: (1/9) h/ μ k =0.56m (c) What is the final velocity of block 1 if d=1m? Ans: (2gh) 1/2 - (8g μ k d) 1/2 =0.81 m/s (leftward) (d) Are the answers the same if block 1 is a rolling cylinder with the same mass? Ans: yes, if the ramp if frictionless (cylinder will slide, not roll); if cylinder rolls, the answers are different due to rotational (rolling) kinetic energy.
A block of mass m falls from rest from a distance h above a mass M which is at rest at the top of a spring of length L when relaxed. When the mass m falls, the two masses stick together, compress the spring, then the spring pushes back and the two masses go up. (a) When is the potential energy stored in the spring maximum and what is it? Ans: when the spring is maximally compressed spring potential energy will be U s =(1/2)kx m 2 where x m is the solution of a quadratic equation, x m = [(m+M)g ± mg{1- 2kh/[g(m+M)]} 1/2 ]/k representing maximum compression of the relaxed spring which is by Mg/k larger than the drawn position. (b) How far up will the two masses go? Ans: H=2(x m -x e ) where x e =(m+M)g/k is the equilibrium position and x m -x e is the amplitude of the oscillations.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Cont (c) What is the maximum velocity of mass m while moving alone? Ans: (2gh) 1/2 , just before it collides with M (d) What is the maximum velocity of the two masses stuck together? Ans: v m =(x m -x e ) ω where ω =(k/(m+M)) 1/2
The 0.5 kg iron ball shown is being swung in a vertical circle at the end of a 0.7-m long string. (a) How slowly can the ball go through its top position without

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 05/23/2011 for the course PHY 2048 taught by Professor Field during the Spring '08 term at University of Florida.

### Page1 / 16

ReviewAnswers - Phys 2101 Review problems In the figure...

This preview shows document pages 1 - 6. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online