11_1_to_11_2_sol

11_1_to_11_2_sol - Student’s Name: REVIEW SECTIONS 11.1...

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Unformatted text preview: Student’s Name: REVIEW SECTIONS 11.1 — 11.2 Show all work to get full credit. Question 1: (1 point) [11.1.13PT]The first four terms of the sequence {(—1)"+1(1.+ airfare ‘H ; .L c w m .=@ z 625 64 9 _ . 1+ ‘, ‘3 Emmi “2' 02= (*3 '(4 +1.): (4%) = E —2’%=_%’% )E’rH 23 'n32 . n:?>: o = (4 +l) ;b = 2:_%:%1—% ‘5 3 "7) ' Question 2: (1 point) [11.1.1bPT]The first four terms of the recursive sweguenceflgiven imm = 2,an=1—2an_1are 0W:® an: 4-2qn. \ C None of these “:2. a-” {_ 2‘1 x t: 23713 ' 2‘ “L ‘. =4-2.2: 5 \-2ab B 2,—3,7,-13 14:5: (13): 1-20.2. \- g“? z: 2, —5,5, —9 Question 3: (1 point) . [11.1.1bPT]The first four terms of the recumiygsmemgggggigqu a1 = 2aan=—a:_1 are Qi;@ O." :. ~ [I 2,—1,3,—12 ":2{ a 2 _ A n-l C 2,-%,6,-‘§' 2 OJ. ‘ "n: h. a 2,—1,3,—§ : — 9- :@ “Avg, / C N f h :— ;oneotesem:5iagt -é=__ _ : Question 4: (1 point) 01 , ' ‘ [11.1.1cPT] The a” term of the sequence 1, —%, i —Ifi‘—-' -~ - is A I 81’ 249 c (—1)n(2—;fi)" .9 mi ‘. six—D (E; = :é.‘ (mt i) X : :—:::::;%;:::-w=aa or; g a. — a > :I! : 4 _L _ \/ _ _ 3 E '.(_1)n—I(fi)n fin 0‘ 7L )Z(| " A- ) “'2‘ Oz:(‘\>a(%): ‘ Question 5.: (1 point) [11.1.2aPT]§::=1(k2 ‘— 2) = _ C 28 V + (27'— Z) (-— Zuchm H51» 2) e—srs 4am; - ' + (41-2) 6.. “HIM; :.(-ID+?_+_-\—+\l}='22 E 13 i 22 isi’ ‘er 2nd term %rc\ 4am I] 14 ik“ Uni LE3: Question 6: (1 point) i z z 5' x 2: [11..1.2aPT]2:=1(—1)k2k= (-0 2' + (—0 2 + (-0 2 E 14 m - '* b‘a—Mk c 30 =—2+L+-9_+m +931 m, a 10 : 2 “(:9 _ = )0 C 10 Asia‘ch Question 7: (1 point) [11.1.2bPT]Select the summation notation for + £7 - - - - E None of these 0 1 _ \ Z _ Z _ u zi=o(—1)“(§)"+"> \<=o (‘0 $3) :5 W 3— X - zz=l(-1)'°(§)’=+l-> lair a1: (-0 (2.5,) = -‘V) 043 (—0"(%)=‘—25—Q E: 28:1(-1)k(§)k k4, a tbl)‘ _2_ ': _p_ h \/ Question 8: (1 point) '9 ‘1 (5) é [ll.1.2bPT]Select the summation notation [email protected] :35 + - . . [3 22:1,”: '—> kzif a1: L : i X L Q’- n 2:2:ot%"—$’i—*3 ~>k=or ac: Uri: % (w 2; I! 229: 9414—1" Ti“ 2‘ Q _ "1 * \kum = (4)12 - ‘2— \/ _(-\)‘°lo to C None ofthese i 21 e 2—,. )03— 2“) =6? Question 9: (1 point) [ll.2.1bPT]The n“I term of an arithmetic sequence with first term cl = e—\ -4 and common difference at = 2 is ' E 271-4 0-1: —— 0‘22. 271—6 0“: (11+ (n—DC\ 2—41: " -1 5 None ofthese — -b' + L“ G 3—471 1 —L‘ + Zn— Question 10: (1 point) [11.2.13PT]The 5” term of an arithmetic sequence with first term (11 = a J2- and common difference :1 = —\/§ is ; —3¢§ alemqarfi— a5 2 CH + (75_\)a 2 D: +HHZ) —- : v2 - Lt E = ‘5flh 3 None of these I: —5\/§ c 4J5 [3 __ Ni a a; Question 11: (1 point) [11.2.1cPT]The 47th term of the arithmetic sequence —§,.- - -} is _ _ ___\_ _ _|_ _ _-\’ c —21 al‘AVZL 2. 5=a2-Q.L’2 l’ 2 c —20 a jf _ 51+ (A; -\)ci ‘ 2 i _ 23> : _ 21 Question 12: (1 point) [11.2.2aPT]Giveh an arithmetic sequence with 0.25 = 80, and an = 125, find the first term (11. a : g0 a1 1. (2g 4M : 90 C 2 4 2e ‘2 =) _ C 3 a4]: 5 Ol+O+i-i>0i = n 5 =>.§ai+25-d:90pém <1 + Mod : \2‘3—9 R1 [3 4 R2-Ri=> 15c}: [+5-_ '3- -C‘ .. Question 13: (1 point) 9 d ' 5 ‘9 al‘ 9045 = 5 [11.2.2bPT]Given an arithmetic sequence with ans = 80, and 0.46 = 140, find the common difference. [3 5 402Q=90=x§a1+250i:90~3m E3 2 Oqg=l1r0 01+h5ci=lli0~> R2 2 : R2_Ri: 200): so 590i:3) Question 14: (1 point) 01 0‘12— [11.2.2cPT]Given the arithmetic sequence @60,—%,~~}, find the sum S41 ‘ \ ‘ E ~539 dzaZPqL; ’2» :3: C —296 Sn 2 ma Jr r1014) (3 E: —450 Z. n —369 " => 81“ :- MOH ALOHA) (#1 : m __ MAO (“fl-H) 2— ; L‘. 3 M , LHO ...
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This note was uploaded on 05/23/2011 for the course MAC 1147 taught by Professor Nuegyen during the Spring '11 term at FSU.

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