{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW_sol(15) - MAC1140-24 Section 4.1 Question 1(1...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: MAC1140-24 Section 4.1 Question 1: (1 point) [4.1.1aMSPT]Select the formulas of ALL oneto-one functions /0 ME) = :43 ——4,> aim-a; Axis —.L. ~A—l— f(:l:) = —2$2 + 3: +miaS5 0‘00, m+ Pas; “orizorfifl’hm ’wi'l‘ “n f(x)=—~2m3+1 nah—«0-1 I ‘ fix I" = —4 ~53 doe-.3 PasS ‘HnL kpfiZOrd’Z'A JD f(:1:)=—2.’l:+l=l\m.o~r ——) Q'Wayrg 1 '10'4 Question 2: (1 point) [4.1.1aMSPT]Select the formulas of ALL one-to—one functions ‘1' __> 0AM? J_+a-L RTMP-w—l “if: lag—L J. f($)=‘237+2 —) at..qu .1 —+b—_L I ’Rr f($)=‘3$2‘$'2——>doca md’ PQSSW {wizka-‘im'lnfl‘ é). [- = "3 —3 C‘BA ND" PMS ‘Hu. kuhuyd‘fiL—lrfi 3h»? 'Question 3: (1 point) [4.1.1bMSPT]Select the graphs of ALL one-to-one functions Wiicai I; I I} Wm“ r 1%?! ~ °~ Lona;- ._) a‘wags 1-4m — L ‘ a dug WA VG“ "H‘l Lnri'zm‘kL—Iim 411+ 7 —7 dad) hi} PMS ‘Hv. LurizmH*'nfi- Kym anwsg \«MYn/db) L4, *{n—f— —-—> dng i-‘k—A. Mar ‘ Question 4: (1 point) [4.1.2aPT]Choose the formula. for the inverse of the function f (x) = 4 513' w ssz/ C f_1(-’E) = %2 141L- ' x; J , W- f‘1(m)= 4;” =7fiv<nflc v! / V 4 . r: f-I(a:)=4fl qt“, wzw/Lifl‘hrchugg _ w :7 ‘H L V D f " 1\+q\/ 3‘ ’fi VMIAbb-j Question 5: (1 point) :7 “1 F“ I ‘3’ X Md [4.1.2aPT]Choose the formula. for the inverse of the function f (x) = fi- v its): ‘1‘ H 3.0-1) '— —x +1 —1 —2z:-1 xi "' ‘ ' _, " ‘ ¥ 1 r: f (x): W x-‘z A) m. -74: am T U f"(w)=:‘-;% i , Hutu/H ‘3 f‘lm = 5% 7 7 j my?“ 23H \/. jaw: 1:52; T ‘37,?“ NW «7 pg Alfiqchqn? x &c 3' ‘3 ’ Li" fig—T '. Question 6: (1 point) k. / [4.1.2bPT]If f(:r) = a(:z: — 3)2 + 2 on (woo, 3) and a > 0, then the fife; inverse function is —1 1 , ' (9, 2 CLQwS)‘ *1 given ciumain; 3 f (93) = m on (—00, 3) , H (»oo,3>) E f'1($)=—\/?a—j+30n (—0013) \ 0V No ‘ A) x < 5 Xn;hf__1(fl= JET-1753011 (—oo,3)i)+ «13 : 5-3 @x::\jflg+ 5 Q. L 515 rig T agave —' u _._ )J: “(V-Q +21 I f_1($) = "VET: +3 0“ (2:00) i 7_ X = \31; +5 mfimdk’r; vuicxa (5,02) [3 f—1(a:) = szaun (2,00) .z “Pug-tuna >5 a>0 Question7:(lpoint) +5 —>§J=" 53+?) X<5 / 3 /\ 4.1.2cPT If f(:z:) = —4:1: + 2 on —2,2], then the inverse function 15 [3 , rim = 4;” on [.—6,10] my: in +7. (imam?) o * U f‘1(m)=}4m+§on [—6,10] =>“>r”~‘”‘“7~ ' x “‘3 4 f“(a:) = -_‘-4:1:+% on [—12] ___ Dwain Slhvwimjid [3 f“(x) = 1 on [—2, 2] —4a:+2 , beam»; 3: [3 None of these - QJ —V n 1 Domain (‘j it Question 8: (1 point) ' =? X = :3: V L109.) ) 1(4)‘ ll {4.1.2cPT]If flat) = —4:1: + 1 on [7—2, 1], then the invéEse function is E“: in - i’ —-)Lf:‘\{fl,§‘ —-—) _L\_L:.:‘&q*‘ -—)XI= ail-LT— ‘ ) 01 l . ~ ‘ (Q, ()0) lnAYUehanaL __> t4»: ,%L i fl ‘Mfa‘l chic; X k 3, f_1(x) = -4;+1 on [-359] f“(m) = fin: +1; on [—3, 9] f“($) = +41: + % on [—2, 1] f—1(m) = _ 1+1 on [—211] nnan 3 None of these Question 9: (1 point) m ‘Hu. may. 35 “mg repglno“ LBL Hm git/m Tufk $300+ Hm Ln 3:;(, 6) Draw «Hm LN 31X @ “Hu— nOEchml Wk. This function has no inverse ...
View Full Document

{[ snackBarMessage ]}