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HW_sol(15)

# HW_sol(15) - MAC1140-24 Section 4.1 Question 1(1...

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Unformatted text preview: MAC1140-24 Section 4.1 Question 1: (1 point) [4.1.1aMSPT]Select the formulas of ALL oneto-one functions /0 ME) = :43 ——4,> aim-a; Axis —.L. ~A—l— f(:l:) = —2\$2 + 3: +miaS5 0‘00, m+ Pas; “orizorﬁﬂ’hm ’wi'l‘ “n f(x)=—~2m3+1 nah—«0-1 I ‘ ﬁx I" = —4 ~53 doe-.3 PasS ‘HnL kpfiZOrd’Z'A JD f(:1:)=—2.’l:+l=l\m.o~r ——) Q'Wayrg 1 '10'4 Question 2: (1 point) [4.1.1aMSPT]Select the formulas of ALL one-to—one functions ‘1' __> 0AM? J_+a-L RTMP-w—l “if: lag—L J. f(\$)=‘237+2 —) at..qu .1 —+b—_L I ’Rr f(\$)=‘3\$2‘\$'2——>doca md’ PQSSW {wizka-‘im'lnﬂ‘ é). [- = "3 —3 C‘BA ND" PMS ‘Hu. kuhuyd‘ﬁL—lrﬁ 3h»? 'Question 3: (1 point) [4.1.1bMSPT]Select the graphs of ALL one-to-one functions Wiicai I; I I} Wm“ r 1%?! ~ °~ Lona;- ._) a‘wags 1-4m — L ‘ a dug WA VG“ "H‘l Lnri'zm‘kL—Iim 411+ 7 —7 dad) hi} PMS ‘Hv. LurizmH*'nﬁ- Kym anwsg \«MYn/db) L4, *{n—f— —-—> dng i-‘k—A. Mar ‘ Question 4: (1 point) [4.1.2aPT]Choose the formula. for the inverse of the function f (x) = 4 513' w ssz/ C f_1(-’E) = %2 141L- ' x; J , W- f‘1(m)= 4;” =7ﬁv<nﬂc v! / V 4 . r: f-I(a:)=4ﬂ qt“, wzw/Liﬂ‘hrchugg _ w :7 ‘H L V D f " 1\+q\/ 3‘ ’ﬁ VMIAbb-j Question 5: (1 point) :7 “1 F“ I ‘3’ X Md [4.1.2aPT]Choose the formula. for the inverse of the function f (x) = ﬁ- v its): ‘1‘ H 3.0-1) '— —x +1 —1 —2z:-1 xi "' ‘ ' _, " ‘ ¥ 1 r: f (x): W x-‘z A) m. -74: am T U f"(w)=:‘-;% i , Hutu/H ‘3 f‘lm = 5% 7 7 j my?“ 23H \/. jaw: 1:52; T ‘37,?“ NW «7 pg Alfiqchqn? x &c 3' ‘3 ’ Li" fig—T '. Question 6: (1 point) k. / [4.1.2bPT]If f(:r) = a(:z: — 3)2 + 2 on (woo, 3) and a > 0, then the ﬁfe; inverse function is —1 1 , ' (9, 2 CLQwS)‘ *1 given ciumain; 3 f (93) = m on (—00, 3) , H (»oo,3>) E f'1(\$)=—\/?a—j+30n (—0013) \ 0V No ‘ A) x < 5 Xn;hf__1(ﬂ= JET-1753011 (—oo,3)i)+ «13 : 5-3 @x::\jﬂg+ 5 Q. L 515 rig T agave —' u _._ )J: “(V-Q +21 I f_1(\$) = "VET: +3 0“ (2:00) i 7_ X = \31; +5 mﬁmdk’r; vuicxa (5,02) [3 f—1(a:) = szaun (2,00) .z “Pug-tuna >5 a>0 Question7:(lpoint) +5 —>§J=" 53+?) X<5 / 3 /\ 4.1.2cPT If f(:z:) = —4:1: + 2 on —2,2], then the inverse function 15 [3 , rim = 4;” on [.—6,10] my: in +7. (imam?) o * U f‘1(m)=}4m+§on [—6,10] =>“>r”~‘”‘“7~ ' x “‘3 4 f“(a:) = -_‘-4:1:+% on [—12] ___ Dwain Slhvwimjid [3 f“(x) = 1 on [—2, 2] —4a:+2 , beam»; 3: [3 None of these - QJ —V n 1 Domain (‘j it Question 8: (1 point) ' =? X = :3: V L109.) ) 1(4)‘ ll {4.1.2cPT]If ﬂat) = —4:1: + 1 on [7—2, 1], then the invéEse function is E“: in - i’ —-)Lf:‘\{ﬂ,§‘ —-—) _L\_L:.:‘&q*‘ -—)XI= ail-LT— ‘ ) 01 l . ~ ‘ (Q, ()0) lnAYUehanaL __> t4»: ,%L i ﬂ ‘Mfa‘l chic; X k 3, f_1(x) = -4;+1 on [-359] f“(m) = ﬁn: +1; on [—3, 9] f“(\$) = +41: + % on [—2, 1] f—1(m) = _ 1+1 on [—211] nnan 3 None of these Question 9: (1 point) m ‘Hu. may. 35 “mg repglno“ LBL Hm git/m Tufk \$300+ Hm Ln 3:;(, 6) Draw «Hm LN 31X @ “Hu— nOEchml Wk. This function has no inverse ...
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