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q15_v1_sol

# q15_v1_sol - MAC1140—24 Quiz 15 Sections 10.3 and...

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Unformatted text preview: MAC1140—24 Quiz 15: Sections 10.3 and 10.4 (Version 1) Question 1: (2.5 points) [10.3.3aPT]Select the matrix which is in reduced row'echelon form r [nggﬁ‘mkno ﬂownﬁumhw Em Eigm ' ' ‘30 E116) r None of these (ﬂ 0 o 2, r {0 0 0 Latch? EO ‘H'u. (Xng \cacudj m-aﬁ ® (D 1 (a f‘ 0 0 ‘ [Q 0 1° L{ O )6) ‘21 in ‘Hu, "duud 1 Question 2: (2.5 points) [10.3.4aPT]Choose the correct 9:, y, or 2 value for the solution of the system cml ‘15 m1 #9 JHm ri'aL4‘ Ammo \$1 in g1: 33+231—3z="7 —‘A 1' ‘5 :‘7 Pl ir'»él—Li Ca “4 E 2x—y+4z=11 ~> 3,4 b. M u * 1;; _| H “ “Hy—“=4 L‘a—i "* -~’> 5 r°‘°m r y: 7‘ .2 '5 -j" SiumTLi’io—A, Z 5 r z=-1 —>i»0 "I 2‘ 5 r1 thndh L} in F x=—1 O ’25 r5 —¢'l|’l‘. ~14 9— '8 '21 . y=__5 [I ,2 —5 girl) x+233>2w r5: A 5 -|+ r5 ‘3 0 ~‘ 9v = » — +2z=5 r z: o o 4 o 3_,_:e [in f .5. ‘ Question3:(2.5 points 7 A ’2 MM 5? r5' 7, 5‘29." O '— m 2'5 [10.4.1aP'I‘] -- x r " Saar—5 r 2"” -/zf\,2€ o o -2 o _ x ‘13. .. I 4— ‘0 -i O (43) 9305(4) _ 22 (-5) a: a —92+l0x+33-l2x—53+|22= -2x FHA-j + I+2; (4)427. +35% + 505) "3333 Question 4: (2.5 points) [10.4.2aPT]Se1ect the solution given by Cramer system, where D { r. '33“). z = D/B z = 0/0 None of these 2 = D/C’ z = B/D Extra-credit question: (1 point) [10.3.1aPT]Choose the echelon form of the following matrix ,ELMMAL ‘1 ‘0 5, = [732—3 [23-8-12 1% “[00 1—2 r[oo F10 [01 "[00 r1_?3' 00 3 —4 2 1 —1 2 A: 2 2 3 32—4y+2z=1 x—y+2z=—2 2x+2y+3z=—3 '3 CL —2m+4y+4z m—2y—2z —:1:+2y+2z 2x—4y—4z 2 3 2 B: 3 2 ;.L‘ a? -1 .3. :2 \$ Dz. WL'UFL D E. .D 4Q: »l2_ 9 .--IL Fl: 7‘3— ’8’ "'1 r '0 O "‘1‘!- >’@ 1 ﬁx 1 [, O 0‘ —2 EL 5 7. ’8 rule forvthe following 10 km mg {3"- eaL‘) NVJ ) 133 -.?> Cu-o‘ I‘ll? I’zl“: ' A , .z [(42) 1% n 0 0- r3. Canmt :ttu‘amsﬁtr 35*) khmr‘a‘h 4 m r. 4‘—% 4 "\—£ ‘0 e _ 3, ‘51: :3 0;”; 7 [0’ o 1] 3 —4 1 =1 —-1 —2 2 2 —3 6) @ Ht. .—L| cl : 394m D --I Q. 2. 5 Q) ® -H ' .. | -\ -J. " C 21-!) ...
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