Test1_Part2_sol

# Test1_Part2_sol - Student’s Name MAC1140-24 Review Set for Final Exam Test 1 Material(Part 2 Due Wednesday Question 1(1 point 05‘> ‘0 6 C

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Student’s Name: MAC1140-24 Review Set for Final Exam: Test 1 Material (Part 2) Due Wednesday (12/06/06) Question 1: (1 point) 05‘ > ‘0: 6; C: 8 [3.1.2aPT]The graph of the quadratic function f = 32 + + 8 has I: vertex at (35,3) Veda? X I __\g = _ ___§_ ,_. _5 E: vertex at (—1,-3) 2‘34 2 ‘ vertex at (—43, m1) BL = I)“; 5) = (_ 531+ Q0 3))- 2 I: vertex at (3, -—1) __ 9 ; ‘2 + g [3 vertex at (3, 35) W V __ __ [L Question 2: (1 point) :> (- 2))— ‘3 — [3.3.3aPT]The graph of f := (9::2 + ﬁrm . 2 C crosses the xmaxis at m :z 9 and crosses the x-axis at .7: 2 —-9 : 8 i L C touches the mwaxis at 9: m 9 and crosses the m~axis at n: == —9 :) x : i‘ 3? I _ - 1‘ does not touch or cross the x ans m3“ RGL E crosses the x-axis at :2: = 9 and touches the m-axis at m :2 ~9 1) you REM. C touches the m~axis at m m 9 and touches the rat—axis at a: 2-: m9 st , Question 3: (1 point) , [4.1.23PT10hoose the fonnula for the mwrse of the function f (1:) m '-'——‘ zm] - T' = - +2 -: X-\ NO—hm: :32 f-1(:c) = :Im—zl 7 X) ) ‘ ii? = c W) = ‘> ‘3“ "L 43L x; m +0 - m = m‘ a » <9 - :1 -(JX ﬂ a) 0921+ ‘ : x(3+\) -( +l) E f1(\$)=:x{‘f | X a; _) + = x Question 4: (1 point) FW 3 4. ‘ ﬂaws z i W 3% légi. ) %:oz.a'xa> i / \$0” = ax(0<a<l :-o."(0<a<|)—; #411 ymalww,1<aa/i\$, 3” 741» y=1-—a’”,0< <1 X 1 1 / i Q. (Ma) a 3: -QXU<CQ—>\3: \‘ax (Kc) y: ~ﬂm, <0: GUI“ ?A—C \ P 9t y :almw’u < a < 1\> g: 0L)< (0(a<|)_,achx (Maﬁa—>3: “I = “'0' is 4—: g M , nﬁ,n_._n._._a=____.___n.-_———_— .. Question 5: (1 point) [4.3.1cPT]log¢5(\/§)3 = r‘- [3 ﬂ 03a a ‘ (J 3 \03 = [L B a C % [3 (ﬂy Question 6: (1 point) [4.3.1ePT}The domain of f m 111(63: + 3) is [3 (0,00) QX+5> O a (-%,oo) =7 6x >453 E “M ,"Q -:: X — _. [3 \$2,; > : g x :3 ("2,00) ‘7 x ‘ 5." Question 7: (1 point) [4.3.1ePTjThe domain of f (m) m lu(-—~Bx m 4) is E “ma-a) mum U (0’00) — Qx > L} E [—§:°0) — b (~oo,—§ :1) X <:L: I: “god —7 *9“) ‘ Question 8: (1 point) ' [4.3.2aMSPT]Select ALL the correct equazions 501' the given graph. 4% > g: loge} (0<Q.<l) None of these 7 L yz—loga(m,0<a<1 v\$kﬁ "l—ITII'I —% %: logax (0<Q.<l) .9 3:— y : loga(x),0 < a < 1 y = logﬂ(—~m),0 < G <1 9' = " 10ga(—m)1a >1 E? : ‘Oﬁaax (0)0 ———> % > (‘i)°b> Akqu (O<Q<D 4% «l . ...
View Full Document

## This note was uploaded on 05/23/2011 for the course MAC 1147 taught by Professor Nuegyen during the Spring '11 term at FSU.

Ask a homework question - tutors are online