Unformatted text preview: C that makes the equation true. (Sea level is 3,963 miles from the center of the Earth.) C=1,570,536,90 c. Use the value of C you found in the previous question to determine how much the object would weigh in i. Death Valley (282 feet below sea level). W=100.15 lbs ii. the top of Mount McKinley (20,320 feet above sea level). W=99.96lbs 2. The equation h D 2 . 1 = gives the distance, D , in miles that a person can see to the horizon from a height, h , in feet. a. Solve this equation for h . (D/1.2)^2=h b. Long’s Peak in Rocky Mountain National Park, is 14,255 feet in elevation. How far can you see to the horizon from the top of Long’s Peak? Can you see Cheyenne, Wyoming (about 89 miles away)? Explain your answer. You would be able to see 143.27 miles from the top. Yes you would be able to see Cheyenne, 89 is less than 143. MAT/117...
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 Spring '09
 rebello
 Math, Oceanography, Radicals, Equations, sea level, Above mean sea level

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