ffigueroaHW2.docx - Week 2 Homework 24 An AM signal has the...

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Week 2 Homework 24. An AM signal has the equation : v(t)=[15+4sin(44X10^3t]sin(46.5 X 10^6t)V Carrier Frequency Wc=2π f=wc/2π 46.5x10^6/6.2832=7400687.548=740687.55= 7.4MHz Frequency of the modulating signal= Wm=2πf f=wm/2π 44x10^3/6.2832=7002.80112=7002.80= 7.3kHz M=Em/Ec =4/15=.266666= .27 Peak voltage of unmodulated carrier V=Ec/sqrt2= 15/1.4142=10.606=10.60V 30. An audio system requires a frequency response from 50 Hz to 15 kHz for high fidelity. If this signal

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