MATH133_unit 1 _ DB assignment

MATH133_unit 1 _ DB assignment - MATH133 March 23, 2011 The...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
March 23, 2011 The car of my dreams at the present time is a dark Plum, 2011 Dodge Challenger. I found a list of pricing for my dream car at Motor Trends website for $25, 495.00. I went to my personal banking website, Texell Federal Credit Union, and found a personal loan (for a car) to be at a low 3 % apr. After reducing the interest rate by 1% per the “Simple Interest Car Loans” ad, I was left to calculate the amount of interest, monthly payments, and the total cost of my dream car. Below are the calculations WITH the ad from Simple Interest Car Loans; Determine the Interest. I=P*R*T I= 25,495*.02*5 I= 510*5 I=$ 2,250.00 Determine the Total Cost. TC= (P*R) T + P TC= (25,495 *.02) 5 +25,495 TC= (510) 5 TC= 2,250 + 25, 495 TC= $27, 745.00 Model the total cost as a Linear Function, with Time as the Independent Variable. F(T)= (P*R) T +P F(5)= (25,495 *.02) T * P F(5)= (510) * 5 + P F(5)= 2,250 + 25, 495 F(5)= $27, 745.00 Divide total cost by the number of months, to determine the Monthly Payment. TC / M= monthly payment
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 3

MATH133_unit 1 _ DB assignment - MATH133 March 23, 2011 The...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online