This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: b. Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the Earth.) c = 100 ∙ 15705369 = 1570536900 c. Use the value of C you found in the previous question to determine how much the object would weigh in i. Death Valley (282 feet below sea level). 20430 = ft1∙1 mi5820 ft 204305280 miles = 3.86932 mi. ii. the top of Mount McKinley (20,320 feet above sea level). 2. The equation gives the distance, D , in miles that a person can see to the horizon from a height, h , in feet. a. Solve this equation for h . b. Long’s Peak in Rocky Mountain National Park, is 14,255 feet in elevation. How far can you see to the horizon from the top of Long’s Peak? Can you see Cheyenne, Wyoming (about 89 miles away)? Explain your answer. MAT/117 MAT/117...
View
Full
Document
This note was uploaded on 05/22/2011 for the course MAT 117 taught by Professor Alkofahi during the Spring '09 term at University of Phoenix.
 Spring '09
 ALKOFAHI
 Radicals, Equations

Click to edit the document details