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Unformatted text preview: min (mm64262) – Homework 1 – lee – (GEDB00864) 1 This printout should have 20 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A flat circular plate of copper has a radius of . 277 m and a mass of 45 . 8 kg. What is the thickness of the plate? Correct answer: 0 . 0212767 m. Explanation: Let : m = 45 . 8 kg and r = 0 . 277 m . The density of copper is ρ = 8 . 93 × 10 3 kg / m 3 . ρ = m V , for a flat circular plate, so V = π r 2 h = m ρ h = m ρ ( π r 2 ) = 45 . 8 kg (8930 kg / m 3 ) π (0 . 277 m) 2 = . 0212767 m . 002 10.0 points An electron, starting from rest and moving with a constant acceleration, travels 5 . 3 cm in 8 . 3 ms. What is the magnitude of this acceleration? Correct answer: 1 . 53868 km / s 2 . Explanation: Let : d = 5 . 3 cm = 5 . 3 × 10 − 5 m and t = 8 . 3 ms = 0 . 0083 s . Starting from rest with constant acceleration, the distance is d = 1 2 a t 2 a = 2 d t 2 = 2 (5 . 3 × 10 − 5 m) (0 . 0083 s) 2 1 km 1000 m = 1 . 53868 km / s 2 . 003 (part 1 of 2) 10.0 points The rectangular and polar coordinates of a point are ( x, y ) and ( r, θ ), where x = 4 and θ = 33 ◦ . Determine the value of r . Correct answer: 4 . 76945. Explanation: x = r cos θ r = x cos θ = 4 cos 33 ◦ = 4 . 76945 . 004 (part 2 of 2) 10.0 points Determine the value of y . Correct answer: 2 . 59763. Explanation: y = r sin θ = (4 . 76945) sin33 ◦ = 2 . 59763 . 005 (part 1 of 2) 10.0 points A skier squats low and races down a 16 ◦ ski slope. During a 4 s interval, the skier accelerates at 2 . 7 m / s 2 . What is the horizontal component of the skier’s acceleration (perpendicular to the di rection of free fall)? Correct answer: 2 . 59541 m / s 2 . Explanation: Let : θ = 16 ◦ and a = 2 . 7 m / s 2 . a y a x a θ min (mm64262) – Homework 1 – lee – (GEDB00864) 2 a x = a cos θ = (2 . 7 m / s 2 ) cos( 16 ◦ ) = 2 . 59541 m / s 2 . 006 (part 2 of 2) 10.0 points What is the vertical component of the skier’s acceleration? Correct answer: . 744221 m / s 2 . Explanation: a y = a sin θ = (2 . 7 m / s 2 ) sin( 16 ◦ ) = . 744221 m / s 2 . 007 (part 1 of 2) 10.0 points Use linear combinations to solve the system braceleftbigg 6 x + 5 y = 8 4 x + 4 y = 64 Find the value of y . (Answer with 100 if there is no solution.) Correct answer: 8....
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This note was uploaded on 05/24/2011 for the course ENGINEERIN 1 taught by Professor Lee during the Spring '11 term at Sungkyunkwan.
 Spring '11
 LEE

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