report5_soln - The Solution for the 5th Report Chapter 7...

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Chapte 7-37 7-43 As (a) Ea O (b) S h The The (c) Ea Th Ea (d) C h The Ea (e) Cl Ea 7-49 er 7 FC = (gro s a check, ach Cl has has 2 bon has 3 bonds e singly bon e doubly bo ach Cl has he bridging ach termina has 4 bonds e doubly bo ch singly bo has 4 bon ach O has The oup numbe the sum of 1 bond an ds and 4 u s and 2 uns nded O has onded O ha 4 bonds a g O has 2 b al O has 1 s and no un onded O ha onded O ha nds and no 1 bond an e Solutio er) – [numb f formal ch nd 6 unsha unshared e shared elect s 1 bond an s 2 bonds a and no uns bonds and bond and nshared ele s 2 bonds a as 1 bond a o unshared d 6 unshar 1 on for the ber of bond harges sho ared electro electrons, s trons, so FC d 6 unshare and 4 unsha shared elec 4 unshare 6 unshare ctrons, so F and 4 unsha nd 6 unsha d electrons red electro e 5 th Rep ds + numbe uld equal t ons, so FC so FC = 6 – C = 6 – (3 + ed electrons ared electro ctrons, so F ed electron ed electron FC = 4 – (4 ared electro red electron , so FC = 7 ons, so FC
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This note was uploaded on 05/24/2011 for the course ENGINEERIN 1 taught by Professor Lee during the Spring '11 term at Sungkyunkwan.

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report5_soln - The Solution for the 5th Report Chapter 7...

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