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midterm2-2010-solutions

# midterm2-2010-solutions - Name Student No ELE 210...

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Unformatted text preview: Name: Student No: ELE 210 ELECTRONICS I EXAM II (25%) SOLUTIONS Q1 Q2 Q3 TOTAL 35 30 35 100 May 12 ๐กโ , 2010 Answer all three questions. Explain your assumptions. Good Luck! Q1. Consider the BJT circuit below. a) Calculate the voltage gain, ๐ด ๐ฃ = ๐ฃ ๐ /๐ฃ ๐ , and current gain, ๐ด ๐ = ๐ ๐ /๐ ๐ . b) Find the input resistance, ๐ ๐ . c) Determine the maximum undistorted symmetrical output voltage swing. ๐ ๐ต๐ธ = 0 . 7 ๐ ๐ฝ = 200 SOLUTION: a) ๐ ๐ต๐ต = ๐ 1 ๐ 1 + ๐ 2 ๐ ๐ถ๐ถ = 1 . 18 V (1.1) ๐ ๐ต๐ต = ๐ 1 โฃโฃ ๐ 2 = 4 . 7 kฮฉ (1.2) ๐ผ ๐ธ๐ = ๐ ๐ต๐ต โ ๐ ๐ต๐ธ ๐ ๐ต๐ต โ ๐๐ +1 + ๐ ๐ธ = 2 . 13 mA (1.3) โ ๐๐ = ๐ ๐ ๐ผ ๐ธ๐ = 26 ๐ 2 . 13 ๐ = 12 . 2 ฮฉ (1.4) ๐ด ๐ฃ = ๐ ๐ถ โฃโฃ ๐ ๐ฟ โ ๐๐ = 2 . 5 ๐ 12 . 2 = 205 (1.5) ๐ด ๐ = ๐ ๐ถ ๐ ๐ถ + ๐ ๐ฟ ๐ ๐ธ ๐ ๐ธ + โ ๐๐ = 0 . 47 (1.6) b) ๐ ๐ = ๐ ๐ธ โฃโฃ โ ๐๐ = 11 . 5 ฮฉ (1.7) c) ๐ ๐๐ = ๐ ๐ถ + ๐ ๐ธ = 5 . 2 kฮฉ (1.8) ๐ ๐๐ = ๐ ๐ถ โฃโฃ ๐ ๐ฟ + ๐ ๐ธ = 2 . 7 kฮฉ (1.9) ๐ผ ๐ถ๐ = 2 . 13 mA (1.10) ๐ ๐ถ๐ธ๐ = ๐ ๐ถ๐ถ โ ๐ผ ๐ถ๐...
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midterm2-2010-solutions - Name Student No ELE 210...

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