{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

set07new

# set07new - ECE3050 Homework Set 7 1 For the CE amplier...

This preview shows pages 1–2. Sign up to view the full content.

ECE3050 Homework Set 7 1. For the CE ampli fi er shown, let R S = 1 k , R 1 = 300 k , R 2 = 150 k , R 3 = 50 , R C = 4 . 3 k , R E = 5 . 6 k , R L = 20 k , V + = 15 V , V = 15 V , V BE = 0 . 65 V , β = 99 , r x = 20 , r 0 = 50 k , and V T = 25 mV . (a) Show that I E = 1 . 417 mA and V CB = 15 . 386 V . (b) Use the r 0 approximations to show that v o /v s = 43 . 74 , r out = 4 . 169 k , and r in = 6 . 315 k . (c) Show that the clipping levels are v + O = 4 . 964 V and v O = 15 . 62 V . (d) Show that the emitter current which results in symmetrical clipping is I E = 2 . 222 mA . (e) Show that the clipping levels for I E = 2 . 222 mA are v + O = v O = 7 . 786 V . 2. For the CC ampli fi er example shown, let R s = 1 k , R 1 = 300 k , R 2 = 150 k , R E = 5 . 6 k , R L = 1 k , V + = 15 V , V = 15 V , V BE = 0 . 65 V , β = 99 , r x = 20 , r 0 = 50 k , V CEsat = 0 . 2 V , and V T = 25 mV . In the ac signal circuit, combine r 0 in parallel with R E from the emitter to ground. This can be done because R tc = 0 , which puts r 0 in parallel with R E . (a) Show that I E = 1 . 417 mA , V CB = 21 . 417 V . (b) Show that v o /v s = 0 . 958 , r out = 27 . 596 , and r in

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

set07new - ECE3050 Homework Set 7 1 For the CE amplier...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online