set07new - ECE3050 Homework Set 7 1. For the CE amplifier...

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Unformatted text preview: ECE3050 Homework Set 7 1. For the CE amplifier shown, let RS = 1 kΩ, R1 = 300 kΩ, R2 = 150 kΩ, R3 = 50 Ω, RC = 4.3 kΩ, RE = 5.6 kΩ, RL = 20 kΩ, V + = 15 V, V − = −15 V, VBE = 0.65 V, β = 99, rx = 20 Ω, r0 = 50 kΩ, and VT = 25 mV. (a) Show that IE = 1.417 mA and VCB = 15.386 V. (b) Use the r0 approximations to show that vo /vs = −43.74, rout = 4.169 kΩ, and rin = 6.315 kΩ. + − (c) Show that the clipping levels are vO = 4.964 V and vO = −15.62 V. (d) Show that the emitter current which results in symmetrical clipping is IE = 2.222 mA. + − (e) Show that the clipping levels for IE = 2.222 mA are vO = −vO = 7.786 V. 2. For the CC amplifier example shown, let Rs = 1 kΩ, R1 = 300 kΩ, R2 = 150 kΩ, RE = 5.6 kΩ, RL = 1 kΩ, V + = 15 V, V − = −15 V, VBE = 0.65 V, β = 99, rx = 20 Ω, r0 = 50 kΩ, VCEsat = 0.2 V, and VT = 25 mV. In the ac signal circuit, combine r0 in parallel with RE from the emitter to ground. This can be done because Rtc = 0, which puts r0 in parallel with RE . (a) Show that IE = 1.417 mA, VCB = 21.417 V. (b) Show that vo /vs = 0.958, rout = 27.596 Ω, and rin = 46.01 kΩ. + − (c) Show that the clipping levels are vO = 3.31 V and vO = −1.20 V. (d) Show that the emitter current which results in symmetrical clipping is IE = 2.661 mA. + − (e) Show that the clipping levels for IE = 2.661 mA are vO = −vO = 2.257 V. 1 3. For the CB amplifier shown, let Rs = 50 Ω, R1 = 300 kΩ, R2 = 150 kΩ, RC = 4.3 kΩ, RE = 5.6 kΩ, RL = 20 kΩ, V + = 15 V, V − = −15 V, VBE = 0.65 V, β = 99, rx = 20 Ω, r0 = 50 kΩ, and VT = 25 mV. (a) Show that IE = 1.417 mA and VCB = 15.386 V. (b) Use the r0 approximations to show that vo /vs = 50.552, rout = 4.202 kΩ, and rin = 17.79 Ω. 2 ...
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This note was uploaded on 05/25/2011 for the course ECE 3050 taught by Professor Hollis during the Summer '08 term at Georgia Tech.

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set07new - ECE3050 Homework Set 7 1. For the CE amplifier...

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