{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

thejfet

# thejfet - c Copywright 2008 W Marshall Leach Jr Professor...

This preview shows pages 1–3. Sign up to view the full content.

c ° Copywright 2008. W. Marshall Leach, Jr., Professor, Georgia Institute of Technology, School of Electrical and Computer Engineering. The JFET Device Equations The circuit symbols for the junction FET or JFET are shown in Fig. 1. There are two types of devices, the n-channel and the p-channel. Each device has gate (G), drain (D), and source (S) terminals. The drain and source connect through a semiconductor channel. A diode junction separates the gate from the channel. For proper operation as an amplifying device, this junction must be reverse biased. This requires v GS < 0 for the n-channel device and v GS > 0 for the p-channel device. Figure 1: JFET circuit symbols. (a) N channel. (b) P channel. The discussion here applies to the n-channel JFET. The equations apply to the p-channel device if the subscripts for the voltage between any two of the device terminals are reversed, e.g. v GS becomes v SG . The JFET must be biased with the gate-source junction reverse biased to prevent the fl ow of gate current, i.e. v GS < 0 for the n-channel device and v GS > 0 for the p-channel device. The gate current is then equal to the reverse saturation current of the junction. This current is very small and is usually neglected in bias and small-signal calculations. However, its e ff ect is included in the noise model given here. The JFET is biased in the active mode or the saturation region when v DS v GS V TO , where V TO is the threshold or pinch-o ff voltage, which is negative. In the saturation region, the drain current is given by i D = β ( v GS V TO ) 2 for v GS V P = 0 for v GS < V TO (1) where β is the transconductance coe cient given by β = β 0 (1 + λv DS ) (2) In this equation, β 0 is the zero-bias value of β , i.e. the value with v DS = 0 , and λ is the channel- length modulation parameter which accounts for the change in β with drain-source voltage. Because i G ' 0 in the pinch-o ff region, the source current is equal to the drain current, i.e. i S = i D . A second way of writing the JFET current is i D = I DSS μ 1 v GS V P 2 for v GS V P = 0 for v GS < V P (3) 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
where I DSS is the drain-source saturation current, i.e. the value of i D with v GS = 0 . It is given by I DSS = βV 2 TO = β 0 (1 + λv DS ) V 2 TO (4) Typical device parameters are β 0 = 2 × 10 4 A/V 2 , V TO = 4 V, and λ = 0 . 01 V 1 . Figure 2 shows the typical variation of the drain current i D with gate-to-source voltage v GS for V TO v GS 0 . The slope of the curve is the small-signal transconductance g m . For v GS < V TO , the drain current is zero. For v GS > 0 , gate current fl ows. Fig. 2 shows the typical variation of drain current i D with drain-to-source voltage v DS for eight values of V GS in the range V TO < V GS 0 . The dashed line separates the linear or triode region from the active or saturation region. In the saturation region, the slope of the curves is the reciprocal of the small-signal drain-source resistance r 0 .
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern