# q02 - i D there are two solutions to the equation for v GS...

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ECE3050Ana logE lectron icsQu iz2 September 2, 2009 Professor Leach Last Name: First Name: Instructions. Print your name in the spaces above. Place a box around any answer. Honor Code Statement: I have neither given nor received help on this quiz. Initials 1o f2 . G iven V + =22V , V = 15 V , R 1 = 220k , R 2 =22k , R C =12k , α =0 . 99 , β =99 ,and V BE =0 . 65V . (a) Solve for R E for I C =1 . 3mA . (b)Ver i fythattheBJTisb iasedinitsact ivemode . V p 22 V n 15 R 1 220000 R 2 22000 R C 12000 α 0.99 β 99 V BE 0.65 I C 0.0013 V BB V p R 2 R 1 R 2 . R BB R p2 R 1 R 2 , V BB 2 = R BB 2 10 4 = V BB V n I C β R BB . V BE I E α R E . R E V BB V n I C β R BB . V BE I C α R E 1.225 10 4 = V CB V p I C R C . V n I C α R E . V CB 5.313 = 2 of 2. (a) The MOSFET drain current is given by i
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Unformatted text preview: i D , there are two solutions to the equation for v GS . What determines the correct one? [The solution for which v GS > V TO .] (b) The gate-source loop bias equation for the MOSFET is V GG − V SS = V GS + I D R SS . When it is used with the equation in part (a), show that this equation leads to a quadratic equation that must be solved for I D . You do not have to solve the quadratic equation. I D R SS + 1 √ K p I C − ( V GG − V SS − V TO ) = 0 1...
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