q12 - ω = 5000 | T 2 ( jω ) | starts at a slope of +1 ,...

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ECE 3050 Analog Electronics Quiz 12 November 11, 2009 Professor Leach Name Instructions. Print your name in the space above. Place a box around your answers. Points will be subtracted if you do not express each numerical answer as a decimal number and if you do not put a box around answers. Honor Code Statement: I have neither given nor received help on this quiz. Initials 1 of 2. On the log-log scales below, sketch the Bode “straight-line” magnitude plots for the transfer functions given. T 1 ( s ) = 5000 1+ s/ 300 (1 + s/ 30) (1 + s/ 5000) T 2 ( s )=300 ( s/ 30) (1 + s/ 300) (1 + s/ 30) (1 + s/ 5000) | T 1 ( ) | starts at 5000 ,breakstoas lopeo f 1 at ω =30 ,she lvesatas lopeo f 0 at ω =300 and a gain of
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Unformatted text preview: ω = 5000 | T 2 ( jω ) | starts at a slope of +1 , shelves at a slope of at ω = 30 and a gain of 300 , breaks to a slope of +1 at ω = 300 , and shelves at a slope of at ω = 5000 and a gain of 5000 . 1 2 of 2. (a) What is the gain of the circuit at dc, i.e. zero frequency. R 3 / ( R 1 + R 3 ) (b) What is the gain at in f nite frequency? ( R 2 k R 3 ) / [ R 1 + ( R 2 k R 3 )] (c) Write the transfer function for V o /V i . It should be in standard time constant form, i.e. all pole and zero terms should be of the form (1 + τs ) , where τ is the time constant. V o V i = R 3 R 1 + R 3 1 + R 2 Cs 1 + [( R 1 k R 3 ) + R 2 ] Cs 2...
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This note was uploaded on 05/26/2011 for the course ECE 3050 taught by Professor Hollis during the Summer '08 term at Georgia Institute of Technology.

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q12 - ω = 5000 | T 2 ( jω ) | starts at a slope of +1 ,...

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