# ccamp - CC Amplifier Example This example makes use of the...

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CC Ampli f er Example This example makes use of the expressions derived in class for the common-collector ampli f er. For the circuits in the f gure, it is given that V + =10V , V = 10V , R s =5k , R 1 = 100k , R 2 = 120k , R E =2k , R L =1k , V BE npn = V EB pnp =0 . 65V , V T =0 . 025V , α =0 . 99 , β =99 , r x =20 ,and r 0 =50 . The capacitors are ac short circuits and dc open circuits. The equations below are written for the NPN circuit. By symmetry, the solutions are the same for the PNP circuit. To understand the solution, you should draw the equivalent circuits for each step. DC Solution To solve for I E , replace the capacitors with open circuits. Look out the base and emitter and form Thévenin equivalent circuits. We have V BB = V + R 2 + V R 1 R 1 + R 2 = 10 × 120k 10 × 100k 100k + 120k = 10 11 R BB = R 1 k R 2 = 100k k 120k =54 . 55k V EE = V = 10 R EE = R E =2k The bias equation for

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ccamp - CC Amplifier Example This example makes use of the...

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