ccamp - CC Amplifier Example This example makes use of the...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
CC Ampli f er Example This example makes use of the expressions derived in class for the common-collector ampli f er. For the circuits in the f gure, it is given that V + =10V , V = 10V , R s =5k , R 1 = 100k , R 2 = 120k , R E =2k , R L =1k , V BE npn = V EB pnp =0 . 65V , V T =0 . 025V , α =0 . 99 , β =99 , r x =20 ,and r 0 =50 . The capacitors are ac short circuits and dc open circuits. The equations below are written for the NPN circuit. By symmetry, the solutions are the same for the PNP circuit. To understand the solution, you should draw the equivalent circuits for each step. DC Solution To solve for I E , replace the capacitors with open circuits. Look out the base and emitter and form Thévenin equivalent circuits. We have V BB = V + R 2 + V R 1 R 1 + R 2 = 10 × 120k 10 × 100k 100k + 120k = 10 11 R BB = R 1 k R 2 = 100k k 120k =54 . 55k V EE = V = 10 R EE = R E =2k The bias equation for
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

ccamp - CC Amplifier Example This example makes use of the...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online