CBAMP - Common-Base Amplifier Example x .y x y Function for...

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Unformatted text preview: Common-Base Amplifier Example x .y x y Function for calculating parallel resistors. R P( x , y ) R1 V plus rx vs 100000 15 R2 120000 RC 4300 0.65 RE VT 5600 0.025 RS β 100 99 RL α 10000 0.99 V minus r0 50000 15 V BE 20 1 With v s = 1, the voltage gain is equal to v o . 1 DC Bias Circuit V BB R BB V plus . R 2 R1 R P R 1, R 2 V BB 1 V BE R BB β V minus . R 1 R2 V BB = 1.364 4 R BB = 5.455 10 V minus IE I E = 2.557 10 3 RE re VT IE r e = 9.777 Test for Active Mode VC VB V CB V plus V minus VC α .I E .R C I E .R E V C = 4.115 V BE V B = 0.031 V CB = 4.146 Thus active mode. VB 2 AC Signal Circuit v te R te R tb v s. RE RS RE v te = 0.982 R te = 98.246 R P R E, R S 0 R tb 1 rx β r' e re r' e = 9.977 3 Circuit for v o R tc R P R C, R L r0 1 R P r' e , R te α . R te r' e R te v te R te R P r' e , r 0 . R tc = 3.007 10 3 r ic 5 r ic = 4.938 10 i csc α .r 0 r0 r' e r' e i csc = 8.987 10 3 vo i csc . R P R tc , r ic v o = 26.862 This is the voltage gain. 4 Circuit for r out r out R P R C , r ic 3 r out = 4.263 10 Circuit for r in r ie r' e . r' e r0 r0 R tc R tc 1 β r ie = 10.569 5 r in R P r ie , R E r in = 10.549 The following solution is based on the r 0 approximations where r 0 is neglected in calculating i csc but not neglected in calculating r ic . G me i csc vc α r' e R te i csc = 8.987 10 3 v te . G me i csc . R P R tc , r ic vc 26.862 . 100 v c = 26.861 3 This is the voltage gain. Percent 26.862 Percent = 3.028 10 This is the percent change from the exact value. r out R P r ic , R C 3 r out = 4.263 10 r in R P r ie , R E r in = 10.549 Approximate solution 1 using the equation i c g m . v b α .I E VT re RE RS . v e and neglecting r x and r 0 . gm r ie g m = 0.101 r ie = 9.777 r ie R te .g . m R P R C, R L Av R E r ie A v = 27.075 r in r out R P R E , r ie RC r in = 9.76 3 r out = 4.3 10 6 Approximate solution 2 using the equation i c α . i e and neglecting r x and r 0 . Av RE RS RE . α .R P R C , R L r ie R te r in = 9.76 3 r out = 4.3 10 A v = 27.075 r in r out R P R E , r ie RC 7 ...
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This note was uploaded on 05/26/2011 for the course ECE 3050 taught by Professor Hollis during the Summer '08 term at Georgia Institute of Technology.

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CBAMP - Common-Base Amplifier Example x .y x y Function for...

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