{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

q03 - TO V GS 5 = V G V GS I D R S V G 8.6 = R 1 R 2 V p V...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
ECE 3050 Analog Electronics Quiz 3 June 3, 2009 Professor Leach Last Name: First Name: Instructions. Print your name in the spaces above. Place a box around any answer. Honor Code Statement: I have neither given nor received help on this quiz. Initials i D = K ( v GS V TO ) 2 g m = 2 p KI D r s = 1 g m r 0 = 1 λ + V DS I D r id = r 0 (1 + g m R ts ) + R ts For credit, you must give all equations that you use to calculate your answers. Credit will not be given for any answer without full supporting work. 1 of 2. For V + = +18 V , R 2 = 120 k , R S = 800 , K = 5 × 10 4 S , and V TO = 2 V , solve for R 1 for I D = 4 . 5 mA . V p 18 K 0.0005 R 2 120000 R S 800 V TO 2 I D 0.0045 V GS I D K V TO
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: TO V GS 5 = V G V GS I D R S . V G 8.6 = R 1 R 2 V p V G 1 . R 1 1.312 10 5 = 2 of 2. For K = 5 × 10 − 4 S , V TO = 2V , I D = 3mA , r id = 50k Ω , R i = 2k Ω , R 1 = 22k Ω , R S = 300 Ω , and R D = 30k Ω , solve for the small-signal voltage gain A v = v o /v i . K 0.0005 V TO 2 I D 0.003 r id 50000 R i 2000 R 1 22000 R S 300 R D 30000 g m 2 K I D . . g m 2.449 10 3 = r s g m 1 r s 408.248 = A v R 1 R i R 1 1 r s R S . R p2 r id R D , . A v 24.268 = 1...
View Full Document

{[ snackBarMessage ]}