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Unformatted text preview: C 1 . (b) Solve For the worst case highpass pole Frequency For C 2 . (c) Solve For the worst case highpass shelving pole and zero Frequencies For C 3 . (d) Solve For the worst case lower cuto± Frequency f L oF the circuit. r ib = r π + (1 + β ) R E b R 3 = 32 . 2kΩ f 1 = 1 2 π ( R s + R 1 b R 2 b r ib ) C 1 = 44 . 7Hz f 2 = 1 2 π ( R C + R L ) C 2 = 7 . 06Hz r ie = R s b R 1 b R 2 + r π 1 + β = 33 . 5 Ω f 3 p = 1 2 π ( r ie b R E + R 3 ) C 3 = 1 . 33Hz f 3 z = 1 2 π ( R E + R 3 ) C 3 = 133 mH f L = r f 2 1 + f 2 2 + f 2 3 p − 2 f 2 3 z = 45 . 3Hz 2...
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This note was uploaded on 05/26/2011 for the course ECE 3050 taught by Professor Hollis during the Summer '08 term at Georgia Tech.
 Summer '08
 HOLLIS

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