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Unformatted text preview: s 2/C 1/r c 2/C ) (Eq. 4) r c r s Substituting Eq. 1 into Eq. 3 gives: d /dt = (T/2 0 L) 1/C (1/r 2/C ) (Eq. 5) Substituting Eq. 5 into Eq. 4 gives: = (d /dt) r 2/C (C/2) ( 1/r s 2/C 1/r c 2/C ) Rearranging d /dt = 2 /(C ( 1/r s 2/C 1/r c 2/C ) r 2/C ) = 2 r s 2/C r c 2/C /(C(r c 2/C r s 2/C ) r 2/C ) 5 At the surface of the spindle r = r s The shear rate can be calculated as: d /dt = 2 r c 2/C /(C(r c 2/C r s 2/C )) For a Newtonian fluid, C = 1 d /dt = 2 r c 2 /(r c 2 r s 2 ) (Eq. 6) The Brookfield software uses Equ. 6 to compute the shear rate, d /dt . By definition, Viscosity, = / (d /dt) Substituting Eq. 1 and Eq. 6 into above = T(r c 2 r s 2 ) / 4 r c 2 r s 2 L The above equation is only valid for a Newtonian fluid....
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 Spring '11
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