This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: s 2/C 1/r c 2/C ) (Eq. 4) Ï‰ r c r s Substituting Eq. 1 into Eq. 3 gives: d Î³ /dt = (T/2 Î· 0 Ï€ L) 1/C (1/r 2/C ) (Eq. 5) Substituting Eq. 5 into Eq. 4 gives: Ï‰ = (d Î³ /dt) r 2/C (C/2) ( 1/r s 2/C 1/r c 2/C ) Rearranging d Î³ /dt = 2 Ï‰ /(C ( 1/r s 2/C 1/r c 2/C ) r 2/C ) = 2 Ï‰ r s 2/C r c 2/C /(C(r c 2/C r s 2/C ) r 2/C ) 5 At the surface of the spindle r = r s The shear rate can be calculated as: d Î³ /dt = 2 Ï‰ r c 2/C /(C(r c 2/C r s 2/C )) For a Newtonian fluid, C = 1 d Î³ /dt = 2 Ï‰ r c 2 /(r c 2 r s 2 ) (Eq. 6) The Brookfield software uses Equ. 6 to compute the shear rate, d Î³ /dt . By definition, Viscosity, Î· = Ï„ / (d Î³ /dt) Substituting Eq. 1 and Eq. 6 into above Î· = T(r c 2 r s 2 ) / 4 Ï‰ r c 2 r s 2 L The above equation is only valid for a Newtonian fluid....
View
Full
Document
This note was uploaded on 05/26/2011 for the course CGN 6505 taught by Professor Mang during the Spring '11 term at University of Florida.
 Spring '11
 Mang

Click to edit the document details