P03 - Project 3 MAC 2311 1 For a function f and number a...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Project 3 MAC 2311 1. For a function f and number a , how is solving the equation f ( x ) = a related to finding f - 1 ( a ) ; what is the important difference (consider sin( x ) )? What property must the function have? 2. Examine the function f ( x ) = x 2 + x . What equation must hold in order for 15 to be in the range of f ? How is this question related to the intersection of the graph of x with the parabola 15 - x 2 ? Consider the intersection of the graph of x with parabolas of the form A - x 2 . Use them to convince yourself that f ( x ) is one-to-one and that 15 is in the range of f . What seems to be the range of f ? What does this tell you about the domain of f - 1 ? Is it easy to write the inverse function f - 1 ( x ) ? Compute f - 1 (2) and f - 1 (18) nonetheless. Using trial and error with a calculator, find a number that is very close to being f - 1 (15) . 2. Solve the logarithmic equations. Why does one yield a false solution? log(4+ x ) - log(1+ x ) = 1 2 log( x ) log(4 - x ) - log(1 - x ) = 1 2 log( x )
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
3. When resistors having resistance r and R
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern