MidTerm2Solution

MidTerm2Solution - PHY 126 hapters 15,16,17 Exam II Mid-term C Problem 1 15 15 points We assume that the total heat flow is approximately the same

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Problem 1 ( 15+15 points) We assume that the total heat flow is approximately the same as it would be through a flat slab of area 0.80 m 2 and thickness 2.0(1.5) cm = 0.020 (0.015) m. (a) The heat current H is then expressed by: J/s. 12 W 12 m 0.020 C 0 C 30 ) m K)](0.80 W/(m 010 . 0 [ 2 = = ° ° = = L T T kA H L H (15 points, the sign is not important so accept the answer with H>0) (b) The total heat flow Q in one day (=86,400 s) is: J. 10 1.0 s) 0 J/s)(86,40 12 ( 6 × = = = Ht Q The quantity of ice melted by this quantity of heat is: kg. 3.0 J/kg) 10 J)/(3.34 10 0 . 1 ( / 5 6 = × × = = f L Q m (15 points) PHY 126 Mid-term Exam II Chapters 15,16,17 J/s. 19 W 19 m 0.015 C 0 C 35 ) m K)](0.80 W/(m 010 . 0 [ 2 = = ° ° = = L T T kA H L H (A) (B) J. 10 1.6 s) 0 J/s)(86,40 19 ( 6 × = = = Ht Q kg. 4.8 J/kg) 10 J)/(3.34 10 6 . 1 ( / 5 6 = × × = = f L Q m (A) (B) (A) (B)
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Problem 2 (30 points) (a)From Bernoulli’s Eq. and use the facts that the velocity of the
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This note was uploaded on 05/28/2011 for the course PHY 126 taught by Professor Staff during the Summer '08 term at SUNY Stony Brook.

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MidTerm2Solution - PHY 126 hapters 15,16,17 Exam II Mid-term C Problem 1 15 15 points We assume that the total heat flow is approximately the same

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