# Quiz3 - Solution: The log is in equilibrium under the...

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PHY126 Quiz No. 3 (Chap.12) Name: A 23-m-long log of irregular cross section is lying horizontally, supported by a wall at one end and a cable attached 4.0 m from the other end, as shown below. The log weighs 7.5 x 10 3 N, and the tension in the cable is 6.2 x 10 3 N. Where is the log’s center of gravity?
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Unformatted text preview: Solution: The log is in equilibrium under the torques exerted by the cable, gravity and the wall. Calculating the torques about the point of contact with the wall (because the other two forces are given), we find: CG x kN) (7.5 m ) 4 23 )( kN 2 . 6 ( = − , so m 7 . 15 = GC x , from the wall....
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## This note was uploaded on 05/28/2011 for the course PHY 126 taught by Professor Staff during the Summer '08 term at SUNY Stony Brook.

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