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Unformatted text preview: Solution: The log is in equilibrium under the torques exerted by the cable, gravity and the wall. Calculating the torques about the point of contact with the wall (because the other two forces are given), we find: CG x kN) (7.5 m ) 4 23 )( kN 2 . 6 ( = − , so m 7 . 15 = GC x , from the wall....
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This note was uploaded on 05/28/2011 for the course PHY 126 taught by Professor Staff during the Summer '08 term at SUNY Stony Brook.
- Summer '08