Quiz7 - distance divided by the speed Therefore kcal 300 =...

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PHY126 Quiz No. 7 (Chap.16) Name: Walking at 3km/h requires an energy expenditure rate of about 200 W. How far would you have to walk to burn off a 300-kcal hamburger? Solution The energy expenditure is the power times the time, while the time required is the
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Unformatted text preview: distance divided by the speed. Therefore kcal 300 ) / ( = = v d P Pt , implies km. 5.23 W) 00 J/kcal)/(2 s)(4184 m/3.6 kcal)(3 300 ( = = d...
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