110211 - Colligative properties of electrolyte solutions,...

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1 CHM3400 - Lecture 15 Feb 11 Colligative properties of electrolyte solutions, biological membranes (Chapter 5 p.170-181) van’t Hoff factor Donnan effect Biological membranes
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2 Van’t Hoff factor actual number of particles in solution at equilibrium number of particles in solution before dissociation i = 1 1 = v i α M v+ X v- v + M z+ + v - X z- N(1- α ) Degree of dissociation: Nv + α Nv - α Examples: Salt i NaCl 2 CuSO 4 2 K 2 SO 4 3
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Example 5.12 The osmotic pressure of a 0.01 m solution of a monoprotic acid HA and a 0.01 m sucrose solution at 298 K are 0.306 atm and 0.224 atm, respectively. Calculate the van’t Hoff factor and the degree of dissociation for HA. Assume ideal behavior and no ion pair formation. Answer : If HA did not dissociate, HA and sucrose would have the same osmotic pressure. Conversely, if HA completely dissociated into H + and A - , the pressure would be expected to be double that of sucrose. 0.306 (atm)
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This note was uploaded on 05/29/2011 for the course CHM 3400 taught by Professor Seabra during the Spring '08 term at University of Florida.

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110211 - Colligative properties of electrolyte solutions,...

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