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Unformatted text preview: ) / 1 /( 2 2 2 2 c v m m = and 2 2 2 2 ) / 1 ( m c v m = which implies that 2 2 2 2 2 / m c v m m = and 4 2 2 2 2 4 2 c m c v m c m = thus 2 2 2 2 ) ( ) ( c m cp E + = . Speed of a particle: Since mv p = and 2 / c E m = we get 2 / c Ev p = and thus 2 2 2 ) ( ) ( c m cp cp E cp c v + = = = . Classically this term is zero and F = ma Time t = 0 F Particle at rest: v = 0, m = m Later time t v Particle moving at speed v, m = m...
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This note was uploaded on 05/29/2011 for the course PHY 3063 taught by Professor Field during the Spring '07 term at University of Florida.
 Spring '07
 Field
 Physics, Energy, Force, Kinetic Energy, Momentum

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