{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Chapter2_15 - Consider the light emitted from a massive...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
PHY3063 R. D. Field Department of Physics Chapter2_15.doc University of Florida Gravity and Light (2) Frame 2 (accelerated, no gravity): In this frame the detector ( i.e. observer) is traveling (toward) the radiation at speed 2 / c V c v g = β and the radiation is “Doppler shifted” according to ( ) 0 2 0 / 1 ) 1 ( λ λ β γ λ c V g obs + = ( ) 0 2 0 / 1 ) 1 ( f c V f f g obs = β γ . Frame 1 (at rest, gravity): The equivalence principle tells us that the same thing must occur in both frame 1 and frame 2. Hence, ( ) 0 2 0 / 1 ) 1 ( λ λ β γ λ c V g obs + = ( ) 0 2 0 / 1 ) 1 ( f c V f f g obs = β γ In this example the light is traveling through a drop in potential, V g = V observer -V source = -gh so λ obs < λ 0 ( i.e. blue shift ).
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Consider the light emitted from a massive star and observed on the Earth. star star star star e e star earth g R GM R GM R GM V V V ≈ + − = − = ∆ In this case, ( ) ( ) star c R GM star g earth star star c V 2 1 / 1 2 + = ∆ + ≈ ( ) ( ) star c R GM star g earth f f c V f star star 2 1 / 1 2 − = ∆ − ≈ and λ obs > λ ( i.e. red shift ). Earth M e R e Inertial frame in a gravity field emitter Frame 1 detector Direction of light V source V observer Massive Star M star R star Direction of light V source...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern