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Unformatted text preview: of the conductor. This implies that ) sin( = ka and hence kL = n where n = 0, 1, 2, 3, and n L = 2 where n = 0, 1, 2, . Cubic Conducting Cavity: For a cavity consisting of a conducting cube with sides of length L get 2 2 2 2 2 z y x n n n c Lf L + + = = where n x , n y , n z = all positive integers . This equation describes all possible wavelengths (or frequencies) of electromagnetic radiation in the cubical conducting cavity. We must count the number of allowed frequencies in the cavity. xaxis yaxis zaxis E B Direction of Propagation One Dimensional Conducting Box . 5 1 n = 1 n = 2 n = 3 yaxis zaxis xaxis O L L L...
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This note was uploaded on 05/29/2011 for the course PHY 3063 taught by Professor Field during the Spring '07 term at University of Florida.
 Spring '07
 Field
 Physics

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