Unformatted text preview: . Also notice that for → ε we have ) ( 2 ) ( ) ) ( ( 2 ) ( ) ) ( ( 2 ) ( 2 2 2 2 2 α h h h m dx x E x m dx x E x V m dx dx x d − = − − = − = ∫ ∫ ∫ + − + − + − Thus, ) ( 2 ) ( 2 ) ( ) ( 2 2 L R x L x R m m dx x d dx x d h h − = − = − − = + = which implies that D m A D 2 2 h − = − − but A = D and hence 2 h m = . Thus there is only one allowed energy ( i.e. one bound state) given by 2 2 2 h m E − = and h h /   ) ( x m e m x − = , where I have normalized ψ (x) so that < ψ  ψ > = 1. x V αδ (x)...
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This note was uploaded on 05/29/2011 for the course PHY 4064 taught by Professor Fields during the Spring '07 term at University of Florida.
 Spring '07
 FIELDS
 mechanics

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