PHY2061 R. D. Field Department of Physics chp31_5.doc University of Florida Discharging a Capacitor After the switch is closed the current is leaving the capacitor so that I = -dQ/dt, where Qis the charge on the capacitor and summing all the potential changes in going around the loop gives QCIR−=0, where I(t)and Q(t)are a function of time. If the switch is closed at t=0 then Q(0)=Q0and QCRdQdt+=0, which can be written in the form dQdtQ= −1τ, where I have defined τ=RC. Dividing by Q and multiplying by dt and integrating gives
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