PHY2061 R. D. Field Department of Physics chp31_5.doc University of Florida Discharging a Capacitor After the switch is closed the current is leaving the capacitor so that I = -dQ/dt, where Qis the charge on the capacitor and summing all the potential changes in going around the loop gives QCIR−=0, where I(t)and Q(t)are a function of time. If the switch is closed at t=0 then Q(0)=Q0and QCRdQdt+=0, which can be written in the form Q=−1τ, where I have defined τ=RC. Dividing by Q and multiplying by dt and integrating gives
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 05/31/2011 for the course PHY 2061 taught by Professor Fry during the Spring '08 term at University of Florida.