20S-CS106A-Practice-Key

# 20S-CS106A-Practice-Key - CS106A Handout 20S April 23rd...

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Unformatted text preview: CS106A Handout 20S April 23rd, 2011 Spring 2011 CS106A Practice Midterm Solution Solution 1: Karel the Beeper Sweeper /** * Implements the program where Karel is initially facing east * and to the left of a 1 by n corridor littered with beepers (where * n >= 2). Karel runs the length of the corridor, collecting all * beepers and placing them where he started out. Assume that * Karel starts out at the corner of 1st and 1st. * * Initially, Karel has no beepers in his bag. */ public class BeeperSweeper extends SuperKarel { public void run() { while (frontIsClear()) { collectAllBeepers(); move(); } collectAllBeepers(); turnAround(); moveToWall(); turnAround(); unloadBeepers(); move(); } private void collectAllBeepers() { while (beepersPresent()) { pickBeeper(); } } private void moveToWall() { while (frontIsClear()) { move(); } } private void unloadBeepers() { while (beepersInBag()) { putBeeper(); } } } 2 Solution 2: Expressions and Methods (2a) 4 + 5.5 / 1.1 - 8 / 3 7.0 "BE" – "BA" error (4 > 6) && (4 / 0 == 8) false (2b) 380 Solution 3: Pythagorean Triples public class PythagoreanTriples extends ConsoleProgram { public void run() { for (int a = 1; a <= LIMIT; a++) { for (int b = a; b <= LIMIT; b++) { int csq = a * a + b * b; int c = GMath.round(Math.sqrt(csq)); if (c * c == csq) { println(a + ", " + b + ", " + c); } } } } /* Maximum value for a and b */ private static final int LIMIT = 25; } Solution 4: SuperHarmonic Numbers public class SuperHarmonics extends ConsoleProgram { public void run() { Rational harmonic = new Rational(0); Rational superHarmonic = new Rational(1); for (int n = 1; n <= LIMIT; n++) { harmonic = harmonic.add(new Rational(1, n)); superHarmonic = superHarmonic.multiply(harmonic); println(n + ".) " + superHarmonic); } } } ...
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