HW1_SOL - Department of Mechanical Science and Engineering...

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Unformatted text preview: Department of Mechanical Science and Engineering ME 300 Thermodynamics Section D Fall 2010 Homework #1 - Solution 1 Problem 1.1 To get familiar with the SI-unit system convert the following temperatures, pressures and velocities. (a) Convert the following temperatures first into C and then into Kelvin.-40 F, 0 F, 32 F, 98.6 F, 212 F, 425 F, 2066 F Analysis : T ( C ) = ( T ( F )- 32) 5 9 (1) T ( K ) = T ( C ) + 273 . 15 (2) Using equation 1 and 2 we get:-40 F = 0 C = 233.15 K (only at 0 F are the numerical values between F and C identical!) F = -17.78 C = 255.37 K (a cold day in Illinois) 32 F = 0 C = 273.15 K (ice point) 98.6 F = 37 C = 310.15 K (approximately body temperature of a human) 212 F = 100 C = 373.15 K (steam point) 425 F = 218.3 C = 491.48 K (baking temperature for pizzas) 2066 F = 1130 C = 1403.15 K (the lowest temperature at which a plain carbon steel can begin to melt) (b) Convert the following pressures into kPa. 14.5 lbf/in. 2 , 34 lbf/in. 2 , 110 lbf/in. 2 , 3190.8 lbf/in. 2 Analysis : P ( kPa ) = P ( lbf/in. 2 ) 6 . 8948 kPa lbf/in. 2 (3) Using equation 3 we get: 14.5 lbf/in. 2 = 100 kPa (roughly atmospheric pressure) 34 lbf/in....
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This note was uploaded on 05/29/2011 for the course ME 300 taught by Professor Staff during the Spring '08 term at University of Illinois, Urbana Champaign.

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HW1_SOL - Department of Mechanical Science and Engineering...

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